
Start with the standard form of a circle, where
is the center of the circle and
is the radius.

Plug in the known values.

This is the circle's equation in standard form.
3/4 + 3/4 = (3 + 3)/4 = 6/4 = 3/2
Question:
Solution:
Let the following equation:
![\sqrt[]{12-x}=\text{ x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B12-x%7D%3D%5Ctext%7B%20x%7D)
this is equivalent to:
![(\sqrt[]{12-x})^2=x^2](https://tex.z-dn.net/?f=%28%5Csqrt%5B%5D%7B12-x%7D%29%5E2%3Dx%5E2)
this is equivalent to:

this is equivalent to:

thus, we can conclude that
x= 3.
Let the width be 2w. Then the lenght is 5w. So:
(2w)(5w)=490
10w²=490
w²=49
w=±7
So, 2w=width=14 in; and 5w=length=35 in
☺☺☺☺
Answer:
gosh...…. dang brainly why do you have to be like that. you were literally trying to help ppl hippo and they just shut you down like that... ugh why rude.
Step-by-step explanation:
im sorry :(