First, what's 3 to the power of 8?
Then what's 3 to the power of 10
Now subtract them by each other for your answer
There are two ways to work this out: normal variables or using "imaginary" numbers.
Normal variables:
![(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}](https://tex.z-dn.net/?f=%20%287%2B2i%29%283-i%29%5C%5C%287%2A3%29%2B%5B7%2A%28-i%29%5D%2B%283%2A2i%29%2B%5B2i%2A%28-i%29%5D%5C%5C21-7i%2B6i-2i%5E%7B2%7D%5C%5C%5C%5C21-i-2i%5E%7B2%7D)
Imaginary numbers:
Using the result from earlier:

Now since

, then the expression becomes:
Answer:
hope this helps
Step-by-step explanation:
192 fl oz. = 6 quarts
to get this you divide the fluid ounces by 32.
A(14)=240(1+0.09)^14-1
A(14)=240(1.09)^13
A(14)=240(3.065)
A(14)=735.79
Make sure the calculations m