A. Rice costs $1.33 per kilogram. How much will 1.3 kg of rice cost?

1 answer:

8 0

A. If a rice costs $1.33 per kilogram, then 1.3 kg will cost 1.33 * 1.3 = 1.729. We can round it $1.73.

B. If a milk costs $0.71 per liter, with $3.00 you can buy 3 / 0.71 = 4.22 liters (after rounding to the hundredth).

C. In (A) we have cost of standard amount and an information how many of rice we want to buy. We find it by multiplying. In (B) we have cost of standard amount and an information about how much money do we have. We find it by dividing.

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Quadrilateral ABCD is a kite. If AD=AB, find AD A. 5/3 B. 7 C. 5/7 D. 22

ICE Princess25 [194]

AD = AB

AD = 2r+8
AB = 5r-13

we need to find the value of r to find the total length

so 2r+8 = 5r-13
subtract 2r from each side:
8 = 3r -13
add 13 to each side:
21 = 3r
divide both sides by 3
r = 21 / 3 = 7
r=7
now we know r, so replace r with 7 in the equation for AD

AD = 2r+8 = 2(7) +8 = 14 +8 = 22

the answer is D. 22

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Perform the indicated operation. (36m 2 - 60m + 25) ÷ (6m - 5)

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A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On

uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

$h(x)=ax(x-7)$ ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

$4=a(3)((3)-7)$

$4=a(3)(-4)$

$\dfrac{4}{(3)(-4)}=a$

$-\dfrac{1}{3}=a$

Putting $a=-\dfrac{1}{3}$ , we get

$h(x)=-\dfrac{1}{3}x(x-7)$ ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

$h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)$