Can you please help me ??

valentina_108 [34]

Answer: $\left\{x | x \in \mathbb{R}, \ -5 \le x < 16\right\}$

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Explanation:

We have some number x such that x is a real number, so we write that as $x \in \mathbb{R}$ which is saying "x is in the real number set".

The portion $-5 \le x < 16$ is how x is restricted. This means x can be -5 or larger, but also must be smaller than 16.

This is from the interval notation [-5, 16). The square bracket means we include -5 as part of the interval, but we exclude 16 because of the curved parenthesis.

The curly braces surrounding everything indicates that we have a set of values.

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Side note:

If x is an integer, then we can get this roster set {-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15} showing all of the integers between -5 and 16, including -5 but excluding 16.

Though chances are your teacher will want you to stick to real numbers rather than just integers.

4 0

4 years ago

If the measures of 2 angles of a triangle are 35 degree and 80 degree then find the measure of its third angle

likoan [24]

Step-by-step explanation:

the 3rd angle = 180 - ( 35+80 ) = 65

7 0

3 years ago

Read 2 more answers

What is 87/200 as a percent

laila [671]

$\frac{87}{200} = 0.435 * 100 = 43.5$ %

5 0

4 years ago

It was reported that uninsured drivers caused 1 in 20 accidents. About 682,494 car crashes were reported. About how many of thes

vivado [14]

To solve the problem you have to take 682,494 and divide it be 20 because 1 in every 20 accidents are caused by that. So, if you divide that you will see what 1 in every 20 is so the equation would be 682,494 div by 20 which will give you 34,124.

7 0

2 years ago

If points A and B are randomly placed on the circumference of a circle with a radius of 2 cm, what is the probability that the l

OLga [1]

Answer:

The probability that the length of chord AB > 2 cm is 2/3 ⇒ D

Step-by-step explanation:

* Lets explain how to solve the problem

- Points A and B are randomly placed on the circumference of a

circle with a radius of 2 cm

- We need to find the probability that the length of chord AB is

greater than 2 cm

- Probability = required length of arc / circumference

- Assume that the length of the chord AB is 2 and the center of

the circle is labeled M

- The radius of the circle is 2 and AB = 2

- In Δ AMB

∵ MA= MB = 2 radii

∵ AB = 2

∴ Δ AMB is an equilateral triangle

∴ m∠AMB = π/3

∵ The length of an arc = r Ф , where r is the radius of the circle and

Ф is the central angle subtended by this arc

∵ r = 2 , Ф = π/3

∴ The length of arc AB = 2 × π/3 = 2π/3

- The arc AB is in the half of the circle then there are another arc

with the same length in the other half of the circle

- The length of the arc we must excluded from the length of the

circle to have the part of length of AB is greater than 2 is

2(2π/3) = 4π/3

∴ The length of the excluded arc is 4π/3

∵ The length of the circle is 2πr

∵ r = 2

∴ The length of the circle = 2π(2) = 4π

- The required arc = length circle - length excluded arc

∵ The length of the excluded arc = 4π/3

∵ The length of the circle = 4π

∴ The required arc = 4π - 4π/3 = 8π/3

- Probability = required length of arc / circumference

∴ Probability = (8π/3)/(4π) = 2/3

∴ The probability that the length of chord AB > 2 cm is 2/3

4 0

3 years ago