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zvonat [6]
2 years ago
10

Find in terms of x the area of the rectangle show Length=3x-1 Width =2x

Mathematics
1 answer:
Ray Of Light [21]2 years ago
8 0

Hey ! there

Answer:

  • Area of rectangle is <u>6</u><u>x</u><u>²</u><u> </u><u>-</u><u> </u><u>2</u><u>x</u>

Step-by-step explanation:

In this question we are given with a rectangle having <u>length </u><u>as </u><u>3x</u><u> </u><u>-</u><u> </u><u>1</u><u> </u>and <u>width </u><u>as </u><u>2</u><u>x</u><u> </u><u>.</u>

And we are asked to find the<u> </u><u>area </u><u>of </u><u>rectangle</u><u> </u><u>in </u><u>terms </u><u>of </u><u>x </u><u>.</u>

For finding area of rectangle we need its Formula . So ,

\qquad \qquad \:      \underline{\boxed{\frak{Area_{(Rectangle)} = l \times w }}}

<u>Where</u><u> </u><u>,</u>

  • l is equal to <u>Length</u><u> of</u><u> rectangle</u>

  • w is equal to<u> </u><u>Width</u><u> of</u><u> rectangle</u>

<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

<u>\dashrightarrow \qquad \:(3x - 1) \times 2x</u>

Now by using distributive property , multiplying 2x with 3x and -1 :

\dashrightarrow \qquad \:2x(3x)  +  2x( - 1)

\dashrightarrow \qquad \:    \red{\underline{\boxed{\frak{6x {}^{2}  - 2x }}}} \quad \bigstar

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>area </u><u>of </u><u>rectangle</u><u> </u><u>is </u><u>6</u><u>x</u><u>²</u><u> </u><u>-</u><u> </u><u>2</u><u>x</u><u> </u><u>.</u>

<u>Note </u><u>:</u> We haven't write the units because in the question no units are given for dimensions.

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
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Rudiy27

Answer:

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Step-by-step explanation:

The number of students in the school in t years after 2002 can be modeled by the following function:

N(t) = N(0)(1+r)^{t}

In which N(0) is the number of students in 2002 and r is the rate of change.

If 1+r>1, the function is a growth function.

If 1-r<1, the function is a decay function.

In 2002, there were 972 students enrolled at Oakview High School.

This means that N(0) = 972

Since then, the number of students has increased by 1.5% each year.

Increase, so r is positive. This means that r = 0.015

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N(t) = N(0)(1+r)^{t}

N(t) = 972(1+0.015)^{t}

N(t) = 972(1.015)^{t}

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N(12) = 972(1.015)^{12}

N(12) = 1162

The number of students enrolled in 2014 is 1162.

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