<h2>
Answer:</h2><h2>x = 13</h2><h2 /><h2>Hope this helps!!</h2>
Answer:
438,012 ways.
Step-by-step explanation:
We have been given that each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7 will not be used. So, there are 23 letters and 6 digits that will be used.
Since the letters and digits can be repeated, so we will use fundamental principal of counting.
For first place, we can use 23 letters, for 2nd and 3rd place we can use 23 letters.
We can use 6 digits for 1st digit place and 6 digit for 2nd digit place as repetition is allowed.
So we can choose coupon code is following ways:
Therefore, we can choose coupon codes in 438,012 ways.
Answer:
500 coins. 2,090 + 1,910 = 4,000. 4,000/8 = 500. hope this helps
Step-by-step explanation:
- Zombie
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
#SPJ4
