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3 years ago

Wat is 2+2? im doing this to give you an extra 2 points!

Mathematics

2 answers:

Mkey [24]3 years ago

8 0

Answer:

Step-by-step explanation:

Thanks btw

Let's pretend the [] are boxes.

[] this is one box.

[] [] these are 2 boxes, which is 2

if you put 2 plus 2,

[] [] + [] []

count them, you get 4

Hooray!

If you dunno how to count, you just see each of the boxes, then count up

1, 2, 3, 4, 5, 6, 7, 8, 9, 10 and so on. when you stop seeing the boxes, stop counting - the number you're on is the answer to your + question!

Iteru [2.4K]3 years ago

6 0

Answer:

oh oh....I know...it's 4....I'm I right

You might be interested in

Solve 7x 12.4=5x-7.6

Zigmanuir [339]

X=-10 hope I helped! :)

6 0

3 years ago

A ball is thrown into the air. The path it takes is modeled by the equation: -3t+24t = h, where t is the time in seconds and h i

astra-53 [7]

Given:

The given equation is:

$-3t^2+24t=h$

Where, t is the time in seconds and h is the height of the ball above the ground, measured in feet.

To find:

The inequality to model when the height of the ball is at least 36 feet above the ground. Then find time taken by ball to reach at or above 36 feet.

Solution:

We have,

$-3t^2+24t=h$

The height of the ball is at least 36 feet above the ground. It means $h\geq 36$ .

$-3t^2+24t\geq 36$

$-3t^2+24t-36\geq 0$

$-3(t^2-8t+12)\geq 0$

Splitting the middle term, we get

$-3(t^2-6t-2t+12)\geq 0$

$-3(t(t-6)-2(t-6))\geq 0$

$-3(t-2)(t-6)\geq 0$

The critical points are:

$-3(t-2)(t-6)=0$

$t=2,6$

These two points divide the number line in 3 intervals $(-\infty,2),(2,6),(6,\infty)$ .

Intervals Check point $-3(t-2)(t-6)\geq 0$ Result

$(-\infty,2)$ 0 $(-)(-)(-)=(-)$ False

$(2,6)$ 4 $(-)(+)(-)=+>0$ True

$(6,\infty)$ 8 $(-)(+)(+)=(-)$ False

The inequality is true for (2,6) and the sign of inequality is $\geq$ . So, the ball is above 36 feet between 2 to 6 seconds.

$6-2=4$

Therefore, the required inequality is $-3t^2+24t\geq 36$ and the ball is 36 feet above for 4 seconds.

3 0

3 years ago

Since the area of the circle is I the area of the square, the

Dovator [93]

Answer:

(b)

$V_2 = \frac{\pi}{4} [ \frac{(2r)^2h}{3}]$ or $V_2 = \frac{1}{3}\pi r^2h$

Step-by-step explanation:

Given

$Ratio = \frac{\pi}{4}$

See attachment for complete question

Required

Determine the volume of the cone

The volume of a square pyramid is:

$V = \frac{a^2h}{3}$

Where

a = base dimension

From the attachment, the base dimension of the square pyramid is 2r.

So:

$a = 2r$

The volume becomes;

$V = \frac{(2r)^2h}{3}$

To calculate the volume of the cone, we simply multiply the given ratio and the volume of the prism.

So, we have:

$V_2 = Ratio * V$

$V_2 = \frac{\pi}{4} [ \frac{(2r)^2h}{3}]$

$V_2 = \frac{\pi}{4} * \frac{(2r)^2h}{3}$

Open bracket;

$V_2 = \frac{\pi}{4} * \frac{4r^2h}{3}$

Cancel out 4

$V_2 = \pi * \frac{r^2h}{3}$

The above can be written as:

$V_2 = \frac{1}{3} * \pi r^2h$

$V_2 = \frac{1}{3}\pi r^2h$

So, we have:

$V_2 = \frac{\pi}{4} [ \frac{(2r)^2h}{3}]$

$V_2 = \frac{1}{3}\pi r^2h$

7 0

3 years ago

Queetlon 10 or 15

Marrrta [24]

Answer:

[B]

Step-by-step explanation:

Given:

People leaving the library were asked how many books they checked out that day The result are: 1,2, 3, 5, 8, 9, 10, 11, 12, 13, 14, 15, 16, 18, 20

To Find:

Which histogram correctly shows the data set?

Solution:
Since it given from the histogram:

0-5, 6-11, 12 - 17,18-23

From the result :

1,2, 3, 5, 8, 9, 10, 11, 12, 13, 14, 15, 16, 18, 20

Thus,

1,2,3,5 = 0-5

8,9,10,11 = 6-11

12,13,14,15,16 = 12-17

18,20 = 18-23

From this we can see that:

for

0 - 5 = 4

6 - 11 = 4

12 - 17 = 5

18 - 23 = 2

Hence, the answer is [B]

Kavinsky

5 0

2 years ago

Help please its due soon

Ann [662]

16 is the answer. I can explain if you need

3 0

3 years ago

Read 2 more answers