Answer:
Option C. is correct choice.
Step-by-step explanation:
Regards: Umer
Answer:
C) (6,2)
Step-by-step explanation:
Rewrite equations:
y=x−4;x+2y=10
Step: Solve y=x−4for y:
y=x−4
Step: Substitute x − 4 for y in x+2y=10:
x+2y=10
x+2(x−4)=10
3x−8=10(Simplify both sides of the equation)
3x−8+8=10+8(Add 8 to both sides)
3x=18
3x
3
=
18
3
(Divide both sides by 3)
x=6
Step: Substitute6forxiny=x−4:
y=x−4
y=6−4
y=2(Simplify both sides of the equation)
Hope this helps!
:)
Answer:
c
Step-by-step explanation:
All the animals will go extinct.
Answer:
(a) P(A1 ∪ A2) = 0.35
Step-by-step explanation:
(a) A1 ∪ A2 :
We start by defining the events.
A1 : '' awarded project 1''
A2 : ''awarded project 2''
A3: ''awarded project 3''
In set theory we write the union of events A and B as A∪B.
A∪B means that the event A occurs,event B occurs or either both events occurs at the same time.
The probability is given by the equation :
P(A∪B) = P(A) + P(B) - P(A∩B) (1)
Where the event (A∩B) is the event where A and B occur at the same time
and P(A∩B) is the probability of (A∩B)
Using the equation (1) :
P(A1 ∪ A2) = P(A1) + P(A2) - P(A1∩A2)
P(A1 ∪ A2) = 0.22 + 0.25 - 0.12
P(A1 ∪ A2) = 0.35
Answer:
A) 0.005
B) 0.001
C)0.0495
Step-by-step explanation:
Let A be the event that an aircraft is present and let B be the event the radar registers its presence.. Thus;
P(A) = Probability that an aircraft is present
P(A') = Probability that an aircraft is not present
P(B) = Probability that the radar generates an alarm
P(B') = Probability that the radar doesn't generate an alarm
Thus from what we are given, we have;
P(A) = 0.05
P(A') = 0.95
P(B) = 0.99
P(B') = 0.01
P(B|A') = 0.1
A) Probability of a false alarm will be;
P(A' ∩ B) = P(A) × P(B|A')
P(A' ∩ B) = 0.05 × 0.1 = 0.005
B) probability of missed detection is;
0.1 × (1 - 0.99) = 0.001
C) probability that an aircraft is present given that the radar registers a presence will be;
P(A ∩ B) = P(A) × P(B)
P(A ∩ B) = 0.05 × 0.99
P(A ∩ B) = 0.0495
