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2 years ago

12

In need this quickly

1 answer:

EastWind [94]2 years ago

8 0

Answer:

are there any other pieces to this problem?

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White raven [17]

8x=6x+20 Btw I figures it out x=10

4 0

3 years ago

Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

or

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

4 0

3 years ago

Help on this please on 16

timama [110]

Answer:

Step-by-step explanation:B

8 0

3 years ago

The quotient of 7 and the difference of a number and 8

tatiyna

The answer would be 1

4 0

2 years ago

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Find the value of x and y.

ozzi

UUUUhhhhhh....i cant really see it sorry.

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3 years ago

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