Question

An Air Force plane flew to the

Answer 1

Answer:

5 hours

Step-by-step explanation:

Time taken for trip : t + 1

Time taken for return : t

Avg. speed (trip) : 256 km/h

Avg. speed (return) : 320 km/h

The distances covered on both trips are equal.

⇒ Distance (trip) = Distance (return)

⇒ Speed (trip) × time (trip) = Speed (return) × time (return)

⇒ (256)(t + 1) = (320)(t)

⇒ 256t + 256 = 320t

⇒ 64t = 256

⇒ t = 4 hours

Time (trip) = t + 1 = 4 + 1 = 5 hours