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Elanso [62]
2 years ago
9

Layla leans a 26-foot ladder against a wall so that it forms an angle of 61° with the ground. How high up the wall does the ladd

er reach? Round your answer to the nearest tenth of a foot if necessary.​
Mathematics
1 answer:
Vesna [10]2 years ago
5 0

Answer:

75 shay

Step-by-step explanation:

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gogolik [260]

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Step-by-step explanation:

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3 years ago
What is the following quotient?
seropon [69]

Answer:  Choice B) \frac{5\sqrt{11}+5\sqrt{3}}{8}\\\\

==========================================

Work Shown:

\frac{5}{\sqrt{11}-\sqrt{3}}\\\\\\\frac{5(\sqrt{11}+\sqrt{3})}{(\sqrt{11}-\sqrt{3})(\sqrt{11}+\sqrt{3})}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{(\sqrt{11})^2-(\sqrt{3})^2}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{11-3}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{8}\\\\\\

This shows why choice B is the answer.

---------------

Explanation:

  • In the second step, I multiplied top and bottom by (\sqrt{11}+\sqrt{3})
  • This is so we can apply the difference of squares rule in step 3. The difference of squares rule is (x-y)(x+y) = x^2-y^2.
  • In step 4, the square roots cancel out with the squaring operation. The two operations are inverses of one another, which is why they cancel.

So in general, if the denominator is \sqrt{a}-\sqrt{b} and you want to rationalize the denominator, then you should multiply top and bottom by \sqrt{a}+\sqrt{b}. The same applies in reverse as well.

This leads to the denominator becoming (\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b}) = (\sqrt{a})^2-(\sqrt{b})^2 = a-b

Keep in mind that a \ge 0 and b \ge 0

4 0
2 years ago
Solve each equation by finding all roots x^4-16=0
Alexandra [31]
Add both sides by 16
so you'll have x^4 =16
take the 4th root of both sides and you'll get x=  2
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What is another name for 23 ten thousands?
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<span>230,000

</span>Hope I Helped You!!! :-)

Have A Good Day!!!
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