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2 years ago

HELP PLEEEAAASEEEE

Mathematics

2 answers:

Alenkasestr [34]2 years ago

8 0

Answer:

154+46×9 is the write answer

Yuki888 [10]2 years ago

4 0

C) p =(154 - 46) x 9 is the correct answer

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Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago

ANSWER QUICK PLEASE THANK YOU!!! 7 1/2 divided by (4 1/2 - 5 1/8)=

DiKsa [7]

Answer:

7 1/2 divided by (4 1/2 - 5 1/8)=-12

Step-by-step explanation:

PLZZ MARK BRAINLIEST!!!!

Answer is -12

8 0

2 years ago

If i won 10 games out of 16, how many games would i need to paly to win 50

MrRa [10]

Ratio is 10:16, so to win 50, its 50:190, so you need to play 190 games to win 50

7 0

3 years ago

Read 2 more answers

two bags contains 10 balls each. Every round you choose with equal probability one of the two bags and pick out a ball. After a

Stells [14]

Answer:

6.10%

Step-by-step explanation:

For every round since we are choosing with equal probability, then the probability of choosing from either of the bags is 1/2

Here, this scenario is only possible when a particular bag has been chosen 10 times and the other bag has been chosen 6 times ( meaning a particular bag has been emptied and for a particular bag to be emptied, all of its content would have been picked)

Now on the 17th trial, an empty bag is chosen

Therefore the required probability will be;

16C0 * (1/2)^10 * (1/2)^6 * 1/2 = 0.0610 = 6.1%

4 0

3 years ago

HELP ME PLEASE!!!!!!!

Diano4ka-milaya [45]

Ill take a guess of... idk. the second or the third one.

5 0

3 years ago

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