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exis [7]
3 years ago
6

Solve this asap

Mathematics
1 answer:
kondaur [170]3 years ago
4 0

Step-by-step explanation:

angle G = 81°

angle CFG = 60°

total angle inside CFG = 180

a+81+60=180

a=39°

In DBCF

Total angle is 360

60+39+138+b=360

b=134°

hope its right :)

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The product of the ages of all teenagers at Joyce’s birthday party last Saturday was 2971987200. The number of 18 year olds who
Elenna [48]

Click here to see ALL problems on Age Word Problems

 Question 1128242: The product of the three ages, in years of three teenagers is 4590. None of the teens are the same ages. What are the ages of the three teen ages? (Use guess and check)

A hat and a jacket cost $100. The jacket cost $90 more than the hat. What are the cost of the hat and the cost of the jacket?

Melody picks a number. She doubles the number, squares are result, divide the square by 3 subtracts 30 from the quotient and gets 18. What are the possible numbers that Melody could have picked? What operation does Melody perform that prevents us from knowing 100% certainly which she picked?

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Answer by greenestamps(9721) About Me  (Show Source):

You can put this solution on YOUR website!

These are three very different problems. The rules of the forum are one problem per post. Please follow those rules in the future.

(1) Certainly guess and check is the easiest way to solve this problem, since you know the three ages are whole numbers. But you should be able to get to the solution with very few if any wrong "guesses" by making your guesses logically.

The product of the three ages is a multiple of 10, and therefore a multiple of 5; since all three ages are in the teens, one of them has to be 15. Then 4590/15 = 306.

You could do guess and check again from there. However, if you note that both the other ages have to be greater than 15, and you know the last digit of the product has to be "6", then the only possible pair of ages is 17 and 18. And indeed 17*18 is 306.

ANSWER: The ages are 15, 17, and 18.

(2) Here is an informal solution method using logical reasoning.

Take away the "extra" $90 that the jacket costs; you are left with a jacket and a hat that each cost the same, and the total is now $100-$90 = $10. That means each of them costs $5. Now add those extra $90 back on to the price of the jacket.

ANSWER: The jacket costs $95; the hat costs $5.

(3) Melody picks a number: Call it x.

 

She doubles the number: It is now 2x.

She squares are result: It is now (2x)^2 = 4x^2.

She divides the square by 3: It is now 4x^2/3.

She subtracts 30 from the quotient: It is now 4x^2/3-30.

The number she ends up with is 18.

Solve the equation that says 4x^2/3-30 = 18:

4x%5E2%2F3-30+=+18

4x%5E2%2F3+=+48

4x%5E2+=+144

x%5E2+=+36

x+=+6 or x+=+-6

ANSWER: The two possible starting numbers are 6 and -6. We get two possible answers because of the step where she squares the number.

6 0
3 years ago
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Find the area of the trapezoid
Cloud [144]

Answer:

area equals to 1/2 a + b * height so I have divided 1/2 which I've taken to divide 4.4 + 3.2 which equals to 7.6 * 3 so 1/2 divide divide 7.6 is 3.8 .3.8 * 3 equals to 11.4 that's my answer 11.4 ft.

Step-by-step explanation:

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6 0
3 years ago
A baseball player comes up to bat 3 times during a league game. He either gets a hit or gets an out. What is the probability tha
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Answer:

Since there are 2 possibilities for each bat (hit or out), the amount of total possibilities is 2 * 2 * 2 = 8. There is only one possibility out of those eight that gives us three hits, therefore the probability is 1 / 8 or 0.125.

4 0
3 years ago
What is the prime factorization of 293? Please explain, too.
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Here if it's not what you need to know just let me know I can explain it if need to be

4 0
4 years ago
The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 30.05 inches

           \sigma   = standard deviation = 0.2 inches

             n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches)  = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z < 3) = 0.99865

 P(X bar <= 30.25) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches)  = 0.99865 - 0.97725

                                                                                       = 0.0214

                                       

7 0
3 years ago
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