PLEASE HELP 10 POINTS!!

Consider the enlargement of the pentagon. A small pentagon has a bottom side length of x centimeters and left side length of 7 c

LuckyWell [14K]

When the pentagon is drawn to scale then its value of x will be x=3.3 cm

<h3>What is the pentagon?</h3>

The pentagon is defined as the shape having five sides connected together.

Now it is given in the question that

For small pentagone

Bottom =x

left =7 cm

For larger pentagone

Bottom=7cm

left=15cm

Now since the pentagon is actually dilated from its size to the new bigger size. It means that the equivalent ratio of both the pentagons will be equal.

For smaller pentagon

$\rm Equivalent \ Ratio = \dfrac{Bottom}{Left} =\dfrac{x}{7}$

For bigger pentagon

$\rm Equivalent \ Ratio = \dfrac{Bottom}{Left} =\dfrac{7}{15}$

Since both, the ratio is the same

$\dfrac{x}{7} =\dfrac{7}{15}$

$x=\dfrac{49}{15} =3.3\ cm$

Thus the pentagon is drawn to scale than its value of x will be x=3.3 cm

To know more about Pentagone follow

brainly.com/question/4804571

4 0

2 years ago

Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%

Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

<em>n</em> = 10

Compute the sample mean and sample standard deviation:

$\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7$

$s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} } = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702$

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a <em>t</em> confidence interval.

The critical value of <em>t</em> for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

$t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262$

*Use a <em>t</em>-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}$

$=176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)$

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

7 0

3 years ago

Given <img src="https://tex.z-dn.net/?f=f%28x%29%20%3Dx%5E2%20-6x%2B8%20and%20g%28x%29%20%3Dx-2" id="TexFormula1" title="f(x) =x

Eva8 [605]

For this case we have the following functions:

$f (x) = x ^ 2-6x + 8\\g (x) = x-2$

We must subtract the functions:

$f (x) -g (x) = x ^ 2-6x + 8- (x-2)\\f (x) -g (x) = x ^ 2-6x + 8-x + 2\\f (x) -g (x) = x ^ 2-7x + 10$

We build a table of values for $x = 0,1,2,3.$

$x = 0, f (x) -g (x) = 0 ^ 2-7 (0) + 10 = 10\\x = 1, f (x) -g (x) = 1 ^ 2-7 (1) + 10 = 1-7 + 10 = 4\\x = 2, f (x) -g (x) = 2 ^ 2-7 (2) + 10 = 4-14 + 10 = 0\\x = 3, f (x) -g (x) = 3 ^ 2-7 (3) + 10 = 9-21 + 10 = -2$

Answer:

$f (x) -g (x) = x ^ 2-7x + 10$

8 0

3 years ago

Tomic and Brooke make a game of shooting free throws. Each basket is worth 2.5 point.Each miss is worth - 0.75 points.Out of 30

Anit [1.1K]

They would have 29.5 point

3 0

3 years ago

Read 2 more answers

the ratio of men and women in a certain factory is 3 to 4. there are 198 men. How many workers are there?

LUCKY_DIMON [66]

3 men

4 women

7 total

3 men/ 7 total = 198 men/ x total

using cross products

3*x = 7 * 198

divide each side by 3

x = 7*198/3

x = 462

There are 462 workers

If you mean 3 men and 1 women for a total of 4 workers when you state a ratio of men and women in a certain factory is 3 to 4.

3/4 =198/x

Using cross products

3x = 4* 198

Divide each side by 3

3x/3 = 4*198/3

x =264

264 workers

It all depends on how you define ratio of men and women in a certain factory is 3 to 4. This is incorrect phrasing and I took it to be men to women. You cannot have a ratio of men and women.

5 0

4 years ago