Ask question

Ask question

All categories

2 years ago

10

2 inches Problem 2: = 2 On the map the scale is 5 inch = 25 miles. How many miles would it be to travel 8 - inches on the map? P

roblem 3:

1 answer:

MAVERICK [17]2 years ago

5 0

Answer:

Map Scale Equivalents

Map Scale Miles to Inches

1:100,000 1.6 miles = 1 inch

1:126,700 2 miles = 1 inch

1:150,000 2.4 miles = 1 inch

1:200,000 3 miles = 1 inch

Step-by-step explanation:

You might be interested in

Pleas answer part A!!!!!!

FrozenT [24]

Answer:

y=120x

Step-by-step explanation:

You can just divide all of the points (y/x) and they all equal to 120. And when you add it to the equation its y=120x

3 0

2 years ago

The area of circle B is 121 times greater than the area of circle A. The radius of circle B is 44. What is the radius of circle

xxMikexx [17]

<em>Formula:</em>
$\bigg( \dfrac{radius_1}{radius_2} \bigg)^2 = \dfrac{area_1}{area_2}$

<em>Plug in the values:</em>
$\bigg( \dfrac{r}{44} \bigg)^2 = \dfrac{1}{121}$

<em>Simplify LHS:</em>
$\dfrac{r^2}{1936} = \dfrac{1}{121}$

<em>Multiply by 1936 on both sides:</em>
$r^2 = \dfrac{1936}{121}
$

<em>Simplify RHS:</em>
$r^2 = 16$

<em>Square root both sides:</em>
$r = 4$

Answer: The radius is 4 units. (Answer B)

5 0

2 years ago

Two cars leave the same parking lot, with one heading north and the other heading east.

Otrada [13]

Answer:

wouldn't it be 3 kilometers because 3 this way plus 3 that way = 6 away from each other?

8 0

3 years ago

What is the factored form of that question

olya-2409 [2.1K]

Answer:

idk but ask your teacher

Step-by-step explanation:

4 0

2 years ago

In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it

gavmur [86]

Answer:

a) $P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b) $P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c) A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

Purchased Gum Kept the Money Total

Students Given 4 Quarters 25 14 39

Students Given $1 Bill 15 29 44

Total 40 43 83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}$

And if we replace we got:

$P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}$

And if we replace we got:

$P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0

3 years ago