Answer:
20 = initial population of the rabbits
1.014 = growth rate of the rabbits
the average rate of change from day 50 to day 100 is 0.8
Step-by-step explanation:
A population of rabbits in a lab, p(x), can be modeled by the function
p(x) = 20(1.014)^x
This model is exponential. Where 20 = initial population of the rabbits
1.014 = growth rate of the rabbits with 1.4% increase rate of the rabbits
To find the average rate of change from day 50 to day 100,
find the population p(50) and p(100). Subtract them and divide by 100 - 50 = 50.
p(50) = 20(1.014)50 = 40.08...
p(100) = 20(1.014)100 = 80.32...
(80.32 - 40.08) / (100 - 50) = 40.24/50 = 0.8048. which is approximately 0.8 to the nearest tenth.
The rate of change is 0.8.
The correct answer is C
3+ 0 is 3
3^2 + 0 is 9
Answer:
<em><u>x=-6, y=-2</u></em>, (As a point) (-6, -2).....The point form is not necessary unless you want to solve the system (of equations) by graphing.
Step-by-step explanation:
By substitution:
x-y=-4 By adding y on both sides,
x=y-4
Now you can substitute x for the expression (y-4)
Plug the (y-4) as x in the other equation.
So -2x+3y=6 becomes
-2(y-4)+3y=6
Now solve:
-2(y-4)+3y=6 distributes out to be
-2y+8+3y=6 Now combining like terms
y+8=6 Subtract 8 on both sides to isolate the variable
<u><em>y=-2</em></u>
Now plug the value -2 in where the y is in any equation (preferably the easier/less complicated one) and solve for x.
So x-y=-4 becomes
x-(-2)=-4
=x+2=-4
=<u><em>x=-6</em></u>
Find the volume of the candle using the formula for volume of a cylinder:
V = PI x r^2 x h = 3.14 x 3.4^2 x 6 = 217.79 cubic cm. Round to 217.8
Find the volume of the block: V = l x w x h = 15 x 12 x 18 = 3,240 cubic cm.
Now divide the volume of the block by the volume of a candle:
3240 / 217.8 = 14.88
Round to the nearest tenth = 14.9 candles.
Given that
3 cos 80° cosec 10° + 2 sin 59° sec 31°
⇛3 cos(90°-10°) cosec 10°+2 sin (90°-31°) sec 31°
We know that
sin (90° - A) = cos A
cos (90°-A) = sin A
⇛3 sin 10° cosec 10° + 2 cos 31° sec 31°
⇛3 sin 10° (1/sin 10°) + 2 cos 31° (1/cos 31°)
⇛3 (sin 10°/sin 10°) + 2 (cos 31°/cos 31°)
⇛3 (1) + 2(1)
⇛3+2
⇛5
<u>Answer</u><u>:</u> Therefore, 3cos 80°cosec 10°+2cos 59°sec 31° = 5.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> (sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^
brainly.com/question/87846?referrer
