$103.92
Process:
64.95/5 = 12.99, 12.99 x 8 = 103.92
Answer: 
<u>Step-by-step explanation:</u>
P(x) = x⁴ - 3x² + 4x + 5
g(x) = x² + 5
<u>_x²_- 8 </u>
x² + 5) x⁴ + 0x³ - 3x² + 4x + 5
-<u>(x⁴ + 0x³ + 5x²) </u> ↓ ↓
-8x² + 4x + 5
-<u>(-8x² + 0x - 40)</u>
4x + 45
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a song should cheer you up you got this i know you do
Answer:
(x, y) =(-6,4)
Step-by-step explanation:
3x-y=-28
-5x-4y=-10
y=3x+28
-5x-4(3x+28)=-10
y=3x+28
-5x-12x-112=-10
y=3x+28
-17x=-10+112
y=3x+28
-17x=102
y=3x+28
x=102/(-17)
y=3x+28
x=-6
y=3*(-6)+28
x=-6
y=-24+28
x=-6
y=4
x=-6
(x,y)=(-6,4)
<u>Answer-</u>
As infinitely many such possible number pairs can be formed, one of the instances of such pair would be (37000 and 307).
<u>Solution-</u>
Suppose the former one is aaaaa and the later one is bbbbb.
The value of 7 in the former is 1000 times greater than in the later, so let's make it 7000 and 7.
Then the numbers will be in the following form,
a7aaa and bbbb7
Again, the value of 3 in the former is 100 times greater than in the later.
Then the numbers will be in the following form,
37aaa and bb3bb7
Substituting all the a's and b's by 0,
we get, 37000 and 307 is a possible set. Replacing 0 with any number from 1-9, will yield another number pair which will satisfy the conditions.
