What you must do for this case is find a function that suits the problem and graph it.
We have:
y: the number of bales in the barn
x: days feeding his cows.
y = -4x + 60 see graphic attached.
Answer:
1) P(0) = 5000
2) P(t --> ∞) = 25000
Step-by-step explanation:
P(t) = (25t² + 125t + 200)/(t² + 5t + 40)
1) Population at the moment corresponds to population at t = 0
P(0) = (25(0²) + 125(0) + 200)/(0² + 5(0) + 40) = (0 + 0 + 200)/(0 + 0 + 40) = 5 thousand = 5000 (P was stated to be in thousands)
2) Population in the long term corresponds to the population as t --> ∞
P(t) = (25t² + 125t + 200)/(t² + 5t + 40)
Divide through the numerator and denominator by t²
P(t) = (25 + (125/t) + (200/t²))/(1 + 5/t + (40/t²))
P(t --> ∞) = (25 + 0 + 0)/(1 + 0 + 0) (Since, (1/∞) = 0)
P(t --> ∞) = 25 thousand = 25000
Answer:
Honestly you can't get it wrong they are all equal to 1.
Hope this helps love
Luv Ya
Times all the numbers together then divide by the number of numbers there are.
D. (5/9v - 5/9)
<u>Step-by-step explanation:</u>
(2/9v)- (-1/3v+ 5/9)
Since it is subtraction, we have to change the sign of the second expression that is after the (-) sign.
= (2/9v + 1/3v - 5/9)
Since we have different denominators, we have to take LCM of 3 and 9 as 3, so the expression becomes,
= (2/9v + 3/9v - 5/9)
= (5/9v - 5/9)
