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ehidna [41]
3 years ago
10

13. A bank account balance starts with $100, has an annual growth

Mathematics
1 answer:
Arlecino [84]3 years ago
8 0

Answer:

See below

Step-by-step explanation:

I <u>THINK</u> this is an account with continuous compouding,

   then the balance after 't' years is    100 e^(.04 t)

        at 0 years      100 e^(.04*0)  = 100 dollars

           12 years      100 e^(.04 * 12 ) = 161.61 dollars

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Step-by-step explanation:

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3 years ago
What is the explicit formula for this sequence?
ddd [48]

Answer:

a_n=-7+4(n-1)

or

a_n=-7+(n-1)(4)

Step-by-step explanation:

-7,-3,1,5,... is a arithmetic sequence.

Arithmetic sequences have a common difference. That is, it is going up by 4 each time.

When you see arithmetic sequence, you should think linear equation.

The point-slope form of a line is y-y_1=m(x-x_1).

m is the common difference, the slope.

Any they are using the point at x=1 in the point slope form.  So they are using (1,-7).

So let's put this into our point-slope form:

y-(-7)=4(x-1)

y+7=4(x-1)

Subtract 7 on both sides:

y=-7+4(x-1)

So your answer is

a_n=-7+4(n-1)

6 0
4 years ago
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Step-by-step explanation:

8 0
3 years ago
James types 90 words in 2 minutes. At this rate, how many words can James type in 15 minutes?
andre [41]
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3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20-%203%20%2B%205i%20%20%5Cdiv%20%20-%203%20-%204i" id="TexFormula1" title=" - 3 + 5i \div
Likurg_2 [28]

Answer:

\frac{-11}{25}+\frac{-27}{25}i given you are asked to simplify

\frac{-3+5i}{-3-4i}

Step-by-step explanation:

You have to multiply the numerator and denominator by the denominator's conjugate.

The conjugate of a+bi is a-bi.

When you multiply conjugates, you just have to multiply first and last.

(a+bi)(a-bi)

a^2-abi+abi-b^2i^2

a^2+0         -b^2(-1)

a^2+-b^2(-1)

a^2+b^2

See no need to use the whole foil method; the middle terms cancel.

So we are multiplying top and bottom of your fraction by (-3+4i):

\frac{-3+5i}{-3-4i} \cdot \frac{-3+4i}{-3+4i}=\frac{(-3+5i)(-3-4i)}{(-3-4i)(-3+4i)}

So you will have to use the complete foil method for the numerator. Let's do that:

(-3+5i)(-3+4i)

First: (-3)(-3)=9

Outer::  (-3)(4i)=-12i

Inner: (5i)(-3)=-15i

Last: (5i)(4i)=20i^2=20(-1)=-20

--------------------------------------------Combine like terms:

9-20-12i-15i

Simplify:

-11-27i

Now the bottom (-3-4i)(-3+4i):

F(OI)L (we are skipping OI)

First:-3(-3)=9

Last: -4i(4i)=-16i^2=-16(-1)=16

---------------------------------------------Combine like terms:

9+16=25

So our answer is \frac{-11-27i}{25}{/tex] unless you want to seprate the fraction too:[tex]\frac{-11}{25}+\frac{-27}{25}i

6 0
3 years ago
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