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docker41 [41]
1 year ago
13

Use the box plots comparing the number of male puppies and number of female puppies attending doggy daycare each day for a month

to answer the questions.
Two box plots shown. The top one is labeled Males. Minimum at 0, Q1 at 1, median at 20, Q3 at 25, maximum at 50. The bottom box plot is labeled Females. Minimum at 0, Q1 at 5, median at 6, Q3 at 10, maximum at 18 and a point at 43

Part A: Estimate the IQR for the males' data. (2 points)

Part B: Estimate the difference between the median values of each data set.

Part C: Describe the distribution of the data and if the mean or median would be a better measure of center for each.

Part D: Provide a possible reason for the outlier in the data set.
Mathematics
1 answer:
dalvyx [7]1 year ago
7 0
  1. The IQR for the males' data is 25.
  2. The difference between the median of the males' data and the female's data is 14.
  3. The distribution of the males' data is skewed to the right and the median would be a better measure of the center. The distribution of the female's data is normal and the mean would be a better measure of the center.
  4. A reason for the outlier is that the number of dogs needing care increased.

<h3>What is the interquartile range?</h3>

The interquartile range for the males data is the difference between the third quartile and the first quartile.

IQR = third quartile - first quartile

25 - 0 = 25

Median = 20 - 6 = 14

An outlier is a number that is way smaller or way larger than that of other numbers in a data set.

To learn more about outliers, please check: brainly.com/question/27197311

#SPJ1

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in a given classroom the number of girls is 10 greater than number of boys if the ratio of the number of girls to the number of
Xelga [282]

Answer:

a) 35,  b) 25,  c) 60

Step-by-step explanation:

The number of girls is 10 more than the number of boys, so it's a good thing to choose a variable to represent the number of boys.

Number of boys:  b

Number of girls:  b + 10

Ratio of girls:boys is 7:5, so

\frac{b+10}{b}=\frac{7}{5}

"Cross multiply" to get

7b=5(b+10)\\7b=5b+50\\2b=50\\b=25

There are 25 boys.  There are 10 more girls, so the number of girls is 35, and the total number of students is 60.

That's a packed classroom!

8 0
2 years ago
she has to make a 25% deposit and 12 monthly payment of $550. How much does she end up paying for the television if it's cash pr
larisa86 [58]
I worked it out in photo.
She pays $8,475

3 0
3 years ago
Can someone help me?<br> (if you can show your work that would be nice).
lubasha [3.4K]

Answer:

1. x1=15.75.

2. 24/48=0.5

3. 24/25=0.96

Step-by-step explanation:

1. 15.75/18=0.875

2. you multiply 48 times 0.5 to find 24.

3. multiply 0.96 with 25 to get 24.

3 0
3 years ago
A researcher studying stress is interested in the blood pressure measurements of chief executive officers (CEOs) of major corpor
sesenic [268]

Answer:

Null Hypothesis, H_0 : \mu = 136 mm Hg  

Alternate Hypothesis, H_A : \mu\neq 136 mm Hg

In this context type I error is rejecting that the μ is equal to 136 mm Hg when in fact μ is equal to 136 mm Hg.

Step-by-step explanation:

We are given that the mean systolic blood pressure, μ, of CEOs of major corporations is different from 136 mm Hg, which is the value reported in a possibly outdated journal article.

He measures the systolic blood pressures of a random sample of CEOs of major corporations and finds the mean of the sample to be 126 mm Hg and the standard deviation of the sample to be 18 mm Hg.

So, Null Hypothesis, H_0 : \mu = 136 mm Hg     {means that the mean systolic blood pressure, μ, of CEOs of major corporations is 136 mm Hg}

Alternate Hypothesis, H_A : \mu\neq 136 mm Hg      {means that the mean systolic blood pressure, μ, of CEOs of major corporations is 136 mm Hg}

Type I error states that the null hypothesis is rejected when in fact the null hypothesis was true. So, in this context type I error is rejecting that the μ is equal to 136 mm Hg when in fact μ is equal to 136 mm Hg.

Suppose the researcher decides not to reject the null hypothesis. It means the researcher is making a type I error.

7 0
3 years ago
How many terms are there in a geometric series if the first terms is 2, the common ratio is 4, and the sum of the series is 2,73
arsen [322]
The sum of n terms of a geometric series is given by
S_{n}=a_{1}\dfrac{r^{n}-1}{r-1}

Substituting the given numbers, you have
2730=2\dfrac{4^{n}-1}{4-1}\\\\2730\dfrac{3}{2}=4^{n}-1\\\\4096=4^{n}\\\\\dfrac{\log(4096)}{\log(4)}=n=6

There are 6 terms in the series.
4 0
3 years ago
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