Question

Use the box plots comparing the number of male puppies and number of female puppies attending doggy daycare each day for a month to answer the questions.
Two box plots shown. The top one is labeled Males. Minimum at 0, Q1 at 1, median at 20, Q3 at 25, maximum at 50. The bottom box plot is labeled Females. Minimum at 0, Q1 at 5, median at 6, Q3 at 10, maximum at 18 and a point at 43

Part A: Estimate the IQR for the males' data. (2 points)

Part B: Estimate the difference between the median values of each data set.

Part C: Describe the distribution of the data and if the mean or median would be a better measure of center for each.

Part D: Provide a possible reason for the outlier in the data set.

Answer 1

1. The IQR for the males' data is 25.
2. The difference between the median of the males' data and the female's data is 14.
3. The distribution of the males' data is skewed to the right and the median would be a better measure of the center. The distribution of the female's data is normal and the mean would be a better measure of the center.
4. A reason for the outlier is that the number of dogs needing care increased.

What is the interquartile range?

The interquartile range for the males data is the difference between the third quartile and the first quartile.

IQR = third quartile - first quartile

25 - 0 = 25

Median = 20 - 6 = 14

An outlier is a number that is way smaller or way larger than that of other numbers in a data set.

To learn more about outliers, please check: brainly.com/question/27197311

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