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2 years ago

In ⊙P, QR≅ST. Which statement must be true? Select all that apply.

1 answer:

5 0

The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π

<h3>The circle with center P</h3>

Given that the circle has a center P

It means that lengths PQ, PR, PS and PT

From the question, we understand that QR = ST.

This implies that triangles QRP and STP are congruent.

i.e. △QRP ≅ △STP is true

<h3>The length of the minor arc</h3>

The given parameters are:

Angle, Ф = 99

Radius, r = 1

The length of the arc is:

L = Ф/360 * 2πr

So, we have:

L = 99/360 * 2π * 1

Evaluate

L = 198/360π

Divide

L = 11/20π

Hence, the length of the minor arc is 11/20π

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Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

$\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}$

and it follows that

$\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}$

7 0

2 years ago

Please help me!!!! precalc question

dangina [55]

Step-by-step explanation:

1. Ampltiude is 1

The period is

$\frac{2\pi}{3}$

is the period

The phase shift is 0

2. The Ampltiude is 2

The period is 2 pi

The phase shift is 1

3. The amplitude is 3

The period is 2 pi/3

The phase shift is -2

4.The amplitude is 2/3

The period is -10pi

The phase shift is 0

5. The Ampltiude is 1

The period is -2 pi

The phase shift is pi

6. The amplitude is 1/4

The period is -4pi

The phase shift is negative 2pi/3

7. The Ampltiude is 3

The period is 4

The phase shift is 8

7 0

3 years ago

At the Olympic games, many events have several rounds of competition. One of these events is the men's 100100100-meter backstrok

padilas [110]

Answer:

Step-by-step explanation:

8 0

3 years ago

Please help, I'll mark Brainiest. It's 8th grade math

yawa3891 [41]

Answer:

(-5, 2)

Step-by-step explanation:

<u>plug x into the equation x - 5y = -15</u>

-5 - 5y = -15

add 5 to both sides: -5y = -10

divide by -5: y = 2

7 0

3 years ago

Read 2 more answers

Solve the System of<br> Equations. Show your work <br><br> Y=x + 6<br> x + y= -2

Flauer [41]

Substitute first Y for the second Y
So it would be x + x + 6 = -2
Then it would be 2x +6 = -2
Move the 6 over so it would be 2x =-8
Divide by 2 your answer is x = -4

4 0

3 years ago