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2 years ago

HELP ASAP PLS.

Mathematics

1 answer:

Sindrei [870]2 years ago

5 0

Step-by-step explanation:

I have no idea if I'm doing it right but my guess would be to take the values that we get from f(x) and g(x) when x = 1. Therefore we get that f(x) is equal to 4 and g(x) is equal to -1. We than just do f/g which is 4/-1 which gives us the final answer of -4 which is option B.

Answer: Option B, -4

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I need help with this its timed so asap.

qaws [65]

Answer:

Height of cactus= 3.8ft

Step-by-step explanation:

Height of palm tree= 4.9ft

Height of cactus= ?

we know, 4.9ft= 1.2ft+c

So, 4.9ft- 1.2ft= c

c= 3.8ft

5 0

3 years ago

Read 2 more answers

Evaluate the expression for x = 2 and y = 4.

Lelu [443]

Answer:

Not enough info

Step-by-step explanation:

Not enough info sry

7 0

2 years ago

The sum of three consecutive even numbers is 48. what is the largest of these numbers?

shutvik [7]

Let's name the three consecutive even numbers n, n+2, and n+4. We know that their sum will be divisible by 2 because they are all even, so we can set x = n/2, and say that x + x+1 + x+2 = 48/2 = 24. Then, we can solve for 3x + 3 = 24, 3x = 24-3 = 21, and x = 21/3 = 7.
Final answer: n/2 = 7, so n = 14, so n+4 (the greatest number) is 14+4 =
18.

3 0

3 years ago

Dan and Camille each have a gift card with a combined balance of $350.00. Dan spent 1/2 of his card balance while Camille spent

dezoksy [38]

It should be around $75

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3 years ago

A firework is launched at the rate of 10 feet per second from a point on the ground 50 feet from an observer. to 2 decimal place

Kazeer [188]

The rate of change of the angle of elevation when the firework is 40 feet above the ground is 0.12 radians/second.

First we will draw a right angle triangle ΔABC, where ∠B = 90°

Lets, assume the height(AB) = h and base(BC)= x

If the angle of elevation, ∠ACB = α, then

tan(α) = $\frac{AB}{BC} = \frac{h}{x}$

Taking inverse trigonometric function, α = tan⁻¹ ( $\frac{h}{x}$ ) .............(1)

As we need to find the rate of change of the angle of elevation, so we will differentiate both sides of equation (1) with respect to time (t) :

$\frac{d\alpha}{dt}=[\frac{1}{1+ \frac{h^2}{x^2}}]*(\frac{1}{x})\frac{dh}{dt}$

Here, the firework is launched from point B at the rate of 10 feet/second and when it is 40 feet above the ground it reaches point A,

that means h = 40 feet and $\frac{dh}{dt}$ = 10 feet/second.

C is the observer's position which is 50 feet away from the point B, so x = 50 feet.

$\frac{d\alpha}{dt}= [\frac{1}{1+ \frac{40^2}{50^2}}] *\frac{1}{50} *10\\ \\ \frac{d\alpha}{dt} = [\frac{1}{1+\frac{16}{25}}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt} = [\frac{25}{41}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt}= \frac{5}{41} =0.1219512$

= 0.12 (Rounding up to two decimal places)

So, the rate of change of the angle of elevation is 0.12 radians/second.

5 0

3 years ago