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wariber [46]
2 years ago
15

What is the weight of the minimum spanning tree found using Kruskal's Algorithm for the graph above? ​

Mathematics
1 answer:
olchik [2.2K]2 years ago
8 0

Answer:

  99

Step-by-step explanation:

Kruskal's Algorithm has you add edges in order increasing weight, skipping ones that create loops.

__

The order of increasing weights for this graph is ...

  10, 12, 14, 16, 18, 22, 24, 25, 28

The edges that can be added without creating loops are shown in bold.

The weight of the minimum spanning tree is ...

  10 +12 +14 +16 +22 +25 = 99

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14. A boy is standing on the top of a tower, observed that the angle of depression of a car on the horizontal ground is 60". On
qaws [65]

The height of the tower is 331.3 meters

The distance from the car to the foot of the tower is 191.3 meters

The situation forms a right angle triangle.

<h3>Right angle triangle:</h3>

Right angle triangle has one of its angles as 90 degrees. Therefore,

The height of the tower is the opposite side of the right angle triangle. The distance from the foot of the tower to the car is the adjacent side of the triangle formed.

Therefore, the following trigonometric can be formed from the relationship.

let

x = adjacent side = distance from the foot of the tower to the car.

Therefore,

x=\frac{140 + h}{tan60}=\frac{h}{tan45}

cross multiply,

(140 + h)(tan 45) = h tan 60

140 tan 45 + h tan 45 = h tan 60

140 tan 45  =  h tan 60 -  h tan 45

140 = h√3 - h

140 = 1.732h - h

140 = 0.732h

h = 140 / 0.732

h = 191.256830601

h = 191.3

Therefore,

height of the tower = 140 + 191.3 = 331.3

The distance from the car to the foot of the tower is as follows;

  • x = 191.3 / tan 45

x = 191.3 / 1

x = 191.3

Therefore, the distance from the car to the foot of the tower is 191.3 meters

learn more on right triangle here; brainly.com/question/26750565?referrer=searchResults

3 0
3 years ago
Can someone help with this ? please i need if done by tomorrow morning
slamgirl [31]
Super blurry so I can’t read it.. could you re-upload it?
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