Answer:
The expression that is greater is a (b - c)
Step-by-step explanation:
- a < 0 and c > b, this means <u>(by the addition property)</u> that c - c > b - c⇒0 > b - c
so for the product <u>a(b - c) </u>we would have a multiplication of a negative number <em>a</em> and another negative number <em>(b - c)</em>. We know that the result of the <u>multiplication of two negative numbers is a positive number.</u>
Therefore, a (b - c) > 0
- a < 0 and c > b, this means <u>by the addition property</u> that c - b > b - b⇒ c - b > 0
so for <u>a(c - b)</u>, we have the negative number <em>a</em> multiplied by the positive number <em>(c - b). </em>We know that the result of the <u>multiplication of a negative number by a positive number is negative. </u>
<u>Therefore a (c - b) < 0</u>
Thus, the expression that is greater is the positive one which is a (b - c)
Y = -x2 + 5x + 36 <span>→ y = -(x2 -5x -36)
</span><span>→ y = -(x2 - 9x +4x - 36)
</span><span>→ y = -[x(x-9) + 4(x - 9)]
</span><span>→ y = -(x - 9)(x + 4)
Your answer would be </span>y=-(x-9)(x+4).
Answer:
Cost of a pound of chocolate chips: $3.5
Cost of a pound of walnuts: $1.25
Step-by-step explanation:
x - cost of a pound of chocolate chips
y - cost of a pound of walnuts
We create two equations based on the information we have:
3x+2y=13
8x+4y=33
The whole point of these problems os to get rid of x or y. In this question, we can do this by multiplying both sides of the first equation by 2, and then subtracting it from the second equation:
8x+4y=33
6x+4y=26
2x=7
x=3.5
Then we change x for 3.5 in the first equation:
3×3.5+2y=13
10.5+2y=13
2y=2.5
y=1.25
Hope this helps!
Answer:
Explanation:
Let's begin writing down everything
(X×(-11)+5)×(-9)+X-55
Now we can multiply
-9(-11X+5)+X-55
99X-45+X-55
And so we get
100X-100
Factorize 100
100(x-1)
All you have to do is take the size for every cereal, divide it with its price and you should get your answer as cents. then compare them all and see which one has the lowest price.
* don't forgot to put place holders and add a decimal.
