How many grams of sodium chloride must be added to make 400. ml of a 0. 600 m sodium chloride
1 answer:
Taking into account the definition of molarity, 14.028 grams of sodium chloride must be added to make 400 mL of a 0.600 M sodium chloride.
<h3>Definition of molarity</h3>Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
Molarity is expressed in units .
In this case, you know:
- Molarity= 0.600 M
- number of moles= ?
- volume= 400 mL= 0.400 L (being 1000 mL= 1 L)
Replacing in the definition of molarity:
Solving:
number of moles= 0.600 M× 0.400 L
number of moles= 0.24 moles
<h3>Mass of sodium chloride</h3>Being the molar mass of sodium chloride 58.45 , that is the amount of mass that a substance contains in one mole, the mass of sodium chloride can be calculated as:
0.24 moles×58.45 = 14.028 grams
Finally, 14.028 grams of sodium chloride must be added to make 400 mL of a 0.600 M sodium chloride.
Learn more about molarity:
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The question requires one to indicate the correct terms for the reactant from left to right.
<h3>What is a reactant?</h3>A reactant is a material that enters and changes during a chemical reaction.
1. Reactant A (Gains/Loses) and electron to become product B
To produce B, reactant A loses one electron. The loss of one electron from an atom causes the atom to be oxidized.
Reactant A gives an electron to NAD+ and is transformed to B+ in the given reaction there is an increase in the positive charge. As a result, reactant A is oxidized to produce B+.
2. NAD+ becomes reduced in the process of the reaction.
NAD+ receives the electron given to it by reactant A and is reduced to NADH. As a result, the positive charge of NAD+ decreases.
3. NADH is more reduced than NAD+
NAD+ receives an electron and becomes NADH. As a result, NADH is decreased more than NAD+
4. NAD+ is in the more oxidized state compared to NADH
NAD+ has a surplus of positive charge as opposed to NADH. NAD+ must receive one electron in order to produce NADH. As a result, as opposed to NADH, NAD+ is more oxidized.
5. Reactant A is the electron donor in this reaction.
Reactant A loses one electron, resulting in positively charged B+. This electron is taken up by NAD+, which reduces to NADH. As a result, the electron donor is reactant A.
6. Reactant A is the reducing agent in this reaction.
A reducing agent is a molecule that can transfer electrons.
Such a molecule has the potential to decrease another molecule while also becoming oxidized. Reactant A is the reducing agent in the given reaction, donating an electron to NAD+.
Following the electron transfer, reactant A is oxidized to product B+, and NAD+ is reduced to NADH.
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