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2 years ago

How many grams of sodium chloride must be added to make 400. ml of a 0. 600 m sodium chloride

1 answer:

5 0

Taking into account the definition of molarity, 14.028 grams of sodium chloride must be added to make 400 mL of a 0.600 M sodium chloride.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

<h3>Moles of sodium chloride</h3>

In this case, you know:

Molarity= 0.600 M
number of moles= ?
volume= 400 mL= 0.400 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

$0.600 M=\frac{number of moles}{0.400 L}$

Solving:

number of moles= 0.600 M× 0.400 L

number of moles= 0.24 moles

<h3>Mass of sodium chloride</h3>

Being the molar mass of sodium chloride 58.45 $\frac{g}{mole}$ , that is the amount of mass that a substance contains in one mole, the mass of sodium chloride can be calculated as:

0.24 moles×58.45 $\frac{g}{mole}$ = 14.028 grams

Finally, 14.028 grams of sodium chloride must be added to make 400 mL of a 0.600 M sodium chloride.

Learn more about molarity:

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