you didn't include the graph
but i'm a guess c.
Answer:
Step-by-step explanation:
Given that X has the following pdf.
x -1 0 2 6 7 Total
P(X) 0.3 0.1 0.3 0.2 0.1 1
xP(X) -0.3 0 0.6 1.2 0.7 2.2
x^2P(X) 0.3 0 1.2 7.2 4.9 13.6
Var(x) 13.6-2.2^2 8.76
Std dev 2.959729717
5) 
6. Find the cumulative distribution function F(x) and calculate F(3.2) =
x -1 0 2 6 7
P(X) 0.3 0.1 0.3 0.2 0.1
F(x) 0.3 0.4 0.7 0.9 1
F(3.2) = P(X<3.2) = ___F(X<6) = 0.7__________
7. E(X) = ______2.2_____
8. Var(X) = ____8.76______
Answer:
-720
Step-by-step explanation:
10x^3y^2 If x = -2 and y = -3
10 * (-2^3) * (-3^2)
10 * (-8) * (9) = -720
8hrs = 480mins
6hrs = 360 mins
472/480 = 0.983...
0.983... x 360 = 354
D) 354