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2 years ago

6

A vegetable garden has 3 tomato plants for every 5 lettuce plants. How many tomato plants are there if there are 45 lettuce plan

ts?
Please help ( no PDF)

1 answer:

adelina 88 [10]2 years ago

6 0

Answer:

the answer is 27

Step-by-step explanation:

because 45 divided by 5 equals 9

and 9 times 3 equals 27

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Can u help me with my workk

eimsori [14]

You knew where to place the target based on the coordinates (-5,4). Starting from the origin (0,0), we know how many units to move to horizontally and vertically. We move the target 5 units to the left, because it is negative. We move the target 4 units up, because it is positive. (x,y)

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3 years ago

Help please! math volumes

salantis [7]

Answer:

980.18 cm^3

Step-by-step explanation:

Volume of cylinder w/out spheres = pi r^2 h

= pi 8^2 *6

now subtract the volume of the TWO spheres

2 * 4/3 pi * 3^3

for result = 980.18 cm^3

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2 years ago

Which is closer to 7?

Anna [14]

Answer:

A. 5.3

Step-by-step explanation:

While both of these numbers are close to 7, 5.3 is the closest and we can find this out with subtraction. So, 9.9 - 7 = 2.9, but 7 - 5.3 = 1.7. Which one can we determine is closer? Well, 2.9 > 1.7, so our answer must be A. 5.3!

Have a nice day and I hope this helped!

8 0

4 years ago

Read 2 more answers

What is the solution to the quadratic equation?<br> y = x^2-4

Anika [276]

(-2,2)

i just did my homework with the same question

7 0

3 years ago

AYUDA CON ESTO!!! ALGUIEN PORFAVOR

Gre4nikov [31]

Answer:

Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

$Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds$

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

$\frac{200}{60} = \frac{10}{3} \approx 3.33$ loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

$\frac{200}{65} = \frac{40}{13} \approx 3.08$ loops per minute

then the period is:

$\frac{13}{40} =0.325\,\,\,minutes$

Therefore runner B has the smaller period

8 0

3 years ago