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Elis [28]
1 year ago
6

There is a population of 15,500 bacteria in a colony. If the number of bacteria doubles every 234 hours, what will

Mathematics
1 answer:
saveliy_v [14]1 year ago
3 0

Answer:

2,48,000

Step-by-step explanation:

  • Initial population of bacteria = 15,500

  • Bacteria doubles after every 234 hours

  • So, after 0 (zero) hours, no of bacteria = 15,500

  • After 234 hours, no. of bacteria = 2(15,500) = 31,000

  • After 468 hours, no. of bacteria = 2(31,000) = 62,000 (2*234 = 468)

  • After 702 hours, no. of bacteria = 2(62,000) = 124,000 (3*234 = 702)

  • After 936 hours, no. of bacteria = 2(124000) = 2,48,000 (4*234 = 936)
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Step-by-step explanation:

~ Here we can see that this problem is set to be so that compound interest is applied ~

1. If compound interest is to be applied, it would be that the "20 percent" is the interest, the principle number ( start value ) ⇒ 12 feet in height, and the time is 10 years.

2. Let us approach this problem step by step. Instead of substiting values into a compound interest formula, let us simply attempt a variation of that process...

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