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Elis [28]
2 years ago
6

There is a population of 15,500 bacteria in a colony. If the number of bacteria doubles every 234 hours, what will

Mathematics
1 answer:
saveliy_v [14]2 years ago
3 0

Answer:

2,48,000

Step-by-step explanation:

  • Initial population of bacteria = 15,500

  • Bacteria doubles after every 234 hours

  • So, after 0 (zero) hours, no of bacteria = 15,500

  • After 234 hours, no. of bacteria = 2(15,500) = 31,000

  • After 468 hours, no. of bacteria = 2(31,000) = 62,000 (2*234 = 468)

  • After 702 hours, no. of bacteria = 2(62,000) = 124,000 (3*234 = 702)

  • After 936 hours, no. of bacteria = 2(124000) = 2,48,000 (4*234 = 936)
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What is the answer to 5t-26=18t
AlladinOne [14]

Answer:

t = -2

Step-by-step explanation:

5t - 26 = 18t

Add 26 to both sides:

5t - 26 + 26 = 18t + 26

Simplify:

5t = 18t + 26

Subtract 18t from both sides:

5t - 18t = 18t + 26 - 18t

Simplify:

-13t = 26

Divide both sides by -13:

-13t/-13 = 26/-13

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t = -2

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3 years ago
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Help pls look at the picture
Alika [10]

Answer:

Option A: -\frac{4}{3} is the correct answer.

Step-by-step explanation:

Given that:

Slope of the line = \frac{3}{4}

Let,

m be the slope of the line perpendicular to the line with slope \frac{3}{4}

We know that,

The product of slopes of two perpendicular lines is equals to -1.

Therefore,

\frac{3}{4}.m=-1\\

Multiplying both sides by \frac{4}{3}

\frac{4}{3}*\frac{3}{4}m=-1*\frac{4}{3}\\

m = -\frac{4}{3}

-\frac{4}{3} is the slope of the line perpendicular to the line having slope \frac{3}{4}

Hence,

Option A: -\frac{4}{3} is the correct answer.

3 0
3 years ago
Which of the following expressions are equivalent to 6^-3?
Rus_ich [418]

1/6^3 is also equivalent to 6^-3. It can be reverted back to 1/216. Answers on ed2020 are A. and D.

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3 years ago
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UkoKoshka [18]

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A. The ability to do something well without wasted time or effort.

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3 years ago
3. Find two possible lengths for CD if C, D, and E
Kaylis [27]

Given :

C, D, and E  are col-linear, CE = 15.8 centimetres, and DE=  3.5 centimetres.

To Find :

Two possible lengths for CD.

Solution :

Their are two cases :

1)

When D is in between C and E .

.                   .           .

C                  D          E

Here, CD = CE - DE

CD = 15.8 - 3.5 cm

CD = 12.3 cm

2)

When E is in between D and C.

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D      E              C

Here, CD = CE + DE

CD = 15.8 + 3.5 cm

CD = 19.3 cm

Hence, this is the required solution.

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