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zysi [14]
2 years ago
8

Solve for x. Round to the nearest tenth, if necessary.

Mathematics
1 answer:
Sphinxa [80]2 years ago
3 0

Answer:

2.8

Step-by-step explanation:

tan = opposite / adjacent

( opposite = side opposite of the angle and adjacent = side length that is not the opposite nor the hypotenuse ( longest side ) )

we are given an angle, ∠E = 26°

tanE = x / 5.7

tan26 = x / 5.7

==> multiply both sides by 5.7

5.7tan26 = x

==> simplify

x = 2.8 ( rounded )

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When purchased, the height of a Japanese maple sapling is 14 inches. The tree is expected to grow 2.5 inches each month. Which f
victus00 [196]

Answer:

Step-by-step explanation:

The initial height of a Japanese maple sapling is 14 inches.

The tree is expected to grow 2.5 inches each month. This increase in height is linear, thus it is in arithmetic progression.

The expression for arithmetic progression is

Tn = a + (n-1)d

Where a = the first term of the series

d = common difference

Tn is the nth term of the series

n = the number of terms.

From the information given

a = 14 inches because it is the initial height of the tree

d = 2.5 because it is the difference in height between 2 consecutive months

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Tn = f(m)

function models the relationship between the height of the tree f(m) and the number of m months of growth will be

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6 0
3 years ago
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
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