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stepan [7]
3 years ago
12

An exponential regression equation relative to the population growth of a state is determined to be = 1.182-(134)", where is the

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
8 0

Answer:

A. 1,998,723

Step-by-step explanation:

1.182(1.34)^49

Aliun [14]3 years ago
4 0
The correct answer is going to be A for this question.
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A football player gained 2 yards on one play . On the next play he gained 5 feet was his gain greater on the first or second pla
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The first play because 1 yard=3 feet and 2 yards=6 feet which is greater then 5 feet. Hope this helps!
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3 years ago
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Simplify the following expressions ( use distributed property )
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-9+3x

2(9-3x)/-2

-(9-3x)

-9+3x

Brainliest?
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3 years ago
6a and 6b are having a competition to see who can make the most money for Red Crescent. 6a make $2 for every $3 that 6b make. If
GaryK [48]

Answer:

45

Step-by-step explanation:

6a 6b

2 : 3

30 : x

<u>30</u><u>×</u><u>3</u>

2

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3 years ago
A pen costs 4.60 Rs. How much will 2 pen cost?
Sav [38]

Answer:

9.20rs

Step-by-step explanation:

4.60*2=9.20

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8 0
3 years ago
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Components of a certain type are shipped to a supplier in batches of ten. Suppose that 50% of all such batches contain no defect
ad-work [718]

Answer:

a) P (0 defective component) = 0.5

   P( 1 defective component ) = 0.35

    P( 2 defective component ) = 0.15

b) P( 0 ) = 0

   p ( 1 ) =  1

   p ( 2 ) = 0.33

Step-by-step explanation:

p( no defective ) = 0.5

p( 1 is defective ) = 0.35

p( 2 is defective ) = 0.15

Given that 2 components are selected at random

<u>a) Given that neither component is defective </u>

Probability of 0 defective component = 0.5

P( 1 defective component ) = 0.35

P( 2 defective component ) = 0.15

<u>b) Given that one of the two tested component is defective </u>

P( 0 defective ) = 0

P( 1 defective ) = P ( \frac{x=1}{x\geq 1} ) = p( x = 1 ) / 1 - P ( x = 0 )

                                        = ( 0.5 )^1 ( 0.5 )^0 /  1 - ( 0.5)^0 (0.5)^1

                                        = 0.5 * 1 / 1 - 0.5 = 0.5 / 0.5 =  1

p ( 2 defective ) = p( x = 3 ) / 1 - P ( x = 0 )

                         = ( 0.5 )^2 ( 0.5 )^0 /  1 - ( 0.5)^0 (0.5)^2

                         = 0.25 / 0.75 = 0.33

<u />

5 0
3 years ago
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