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3 years ago

12

which of the following points would you represent using a negative number? explain what a positive number would represent in tha

t situation.

1 answer:

Alex_Xolod [135]3 years ago

5 0

First plot the points that you are given. If a point is below the x-axis, then it is considered negative.

I hope this helps. I’m not sure what points you are given.

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2g+7=-4g+7+6g how do you solve that

nikklg [1K]

$2g+7=-4g+7+6g \\\\\\ 2g+7=2g+7 \to True \ statement \\\\\\ 2g-2g=7-7 \\\\ \boxed{0=0}$

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4 years ago

Read 2 more answers

-4+3x=8 solve plzzzz

jarptica [38.1K]

Answer:

x=4

Step-by-step explanation:

-4+3x=8

+4 +4

<u>3x</u>=<u>12</u>

3x 3x

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3 years ago

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Triangle ABC Is similar to triangle DEF solve for r

Ymorist [56]

since they're similair then similair sides will be proportional

CB is similair to EF

\frac{6}{8}86 = \frac{3}{4}43

same thing if you try with the hypotenuse AB similair to DE

\frac{13.5}{18}1813.5 = \frac{3}{4}43

So, if you multiply r (DF) by 3/4 you will get the similair side AC

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r= 12÷ 3/4

<h3>r=16.</h3>

<h2>i HOPE IT'S HELP </h2><h3 />

4 0

3 years ago

Kelly is having a party. She wants to make punch. The recipe for punch uses 3 pints of pineapple juice, 5 cups or orange juice,

Maurinko [17]

No, because if you add it up all together her recipe does not call for 20 cups.

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3 years ago

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

<u>Right part:</u>

$\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Since simplified left and right parts are the same, then the equality is true.

3 0

3 years ago