Question

You drop a stick from a height of 64 feet. At the same time, your friend

Answer 1

Using a quadratic function, it is found that:

a) It hits the ground after 2 seconds.

b) Your friend's stick hits the ground 0.83 seconds later.

What is the quadratic function for the projectile's height?

It is given by:

$s(t) = -16t^2 + v(0)t + h(0)$

In which:

• v(0) is the initial velocity.

• h(0) is the initial height.

Item a:

Dropped at rest from a height of 64 feet, hence v(0) = 0, h(0) = 64, so the equation is:

$s(t) = -16t^2 + 64$

It hits the ground when s(t) = 0, hence:

-16t^2 + 64 = 0

t^2 = 4

t = 2.

It hits the ground after 2 seconds.

Item b:

For your friend, we have that h(0) = 144, hence:

-16t^2 + 144 = 0

t^2 = 8.

t = 2.83.

2.83 - 2 = 0.83.

Your friend's stick hits the ground 0.83 seconds later.

More can be learned about quadratic functions at brainly.com/question/24737967