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goblinko [34]
2 years ago
9

How would a small bar magnet be oriented when placed at position x

SAT
1 answer:
JulsSmile [24]2 years ago
4 0

The small bar magnet will be oriented when placed at position x by placing in a corresponding horizontal position in the magnetic field.

<h3>What is Magnetic orientation?</h3>

This is defined as the direction in which it can obtain the best magnetic properties.

The magnet is placed in an horizontal position perpendicular to the direction of the magnetic field thereby making option D the most appropriate choice.

Read more about Magnetic orientation here brainly.com/question/8176201

#SPJ1

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Which process of the enterprise platform interacts with vendors and manages the entire supply chain for a retail client?
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Answer Under enterprise resource planning platform, experience is the process whereby vendors interact and also manage the entire supply chain link on behalf of a retail client. In an enterprise chain, experience is the only process that manages the whole supply chain
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Which economic system is supported by this passage’s main argument?
lord [1]
The answer is Command Economy<span />
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A 100-n weight is hung at the middle of a 4-m long horizontal clothesline. If the middle of the clothesline sags by 1 m, what is
Elena L [17]

The tension on each segment of the clothesline is :  110 N

<u>Given data : </u>

mass of object = 100 n  = 10 kg

Horizontal distance of clothesline = 4 m

middle of clothesline sag s by : 1m

<h3 /><h3>Determine the tension on each segment of clothesline</h3>

<u>First step</u> : calculate the horizontal angle made by the sagging

β = arctan ( 1 m / 2m )  ----- ( 1 )

  = arctan ( 0.5 )

  ≈ 26.57°

Note : Tension in th y axis ( Ty ) = Tsinβ

Therefore :

Tension on each segment can be calculated using the formula below

2Tsinβ - mg = 0

solve for T

T = mg / 2sinβ

  = ( 10 * 9.8 ) / 2 * sin 26.57°

  = 98 / 0.89

  = 110 N

Hence we can conclude that the tension on each segment of the clothesline is : 110 N

Learn more about Tension calculations : brainly.com/question/24994188

7 0
3 years ago
During a rainfall, the depth of water in a rain gauge increases at a rate modeled by r(t)=0.5+tcos(πt380) r ( t ) = 0.5 + t cos
Tresset [83]

The function r(t)= 0.5 + t cos(πt³/80) is an illustration of a cosine function

The depth of water in the rain gauge increases by 1.466cm from t = 0 to t = 3

<h3>How to determine the increase in water depth?</h3>

The function is given as:

r(t)= 0.5 + t cos(πt³/80)

When t = 0, the depth of water is:

r(0)= 0.5 + 0 * cos(π *0³/80)

Evaluate

r(0) = 0.5

When t = 3, the depth of water is:

r(3)= 0.5 + 3 * cos(π *3³/80)

Evaluate

r(3)= 1.966

Calculate the difference (d) in the depths

d = r(3) - r(0)

So, we have:

d = 1.966 - 0.5

Evaluate

d = 1.466

Hence, the depth of water in the rain gauge increases by 1.466cm from t = 0 to t = 3

Read more about cosine functions at:

brainly.com/question/17075439

4 0
3 years ago
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