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drek231 [11]
3 years ago
9

Simplify the expression -3y-(8y+1)

Mathematics
1 answer:
drek231 [11]3 years ago
4 0
−3y−(8y+1)

Distribute the Negative Sign:

=−3y+−1(8y+1)

=−3y+−1(8y)+(−1)(1)

=−3y+−8y+−1

Combine Like Terms:

=−3y+−8y+−1

=(−3y+−8y)+(−1)

=−11y+−1

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How many different ways can you make 82 cents using current u.s. currency
andrew11 [14]
 <span>You can probably just work it out. 

You need non-negative integer solutions to p+5n+10d+25q = 82. 

If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80. 


So this is the same as n + 2d + 5q ≤ 16 

So now you simply have to "crank out" the cases. 

Case q=0 [ n + 2d ≤ 16 ] 

Case (q=0,d=0) → n = 0 through 16 [17 possibilities] 
Case (q=0,d=1) → n = 0 through 14 [15 possibilities] 
... 
Case (q=0,d=7) → n = 0 through 2 [3 possibilities] 
Case (q=0,d=8) → n = 0 [1 possibility] 

Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81 

Case q=1 [ n + 2d ≤ 11 ] 
Case (q=1,d=0) → n = 0 through 11 [12] 
Case (q=1,d=1) → n = 0 through 9 [10] 
... 
Case (q=1,d=5) → n = 0 through 1 [2] 

Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42 

Case q=2 [ n + 2 ≤ 6 ] 
Case (q=2,d=0) → n = 0 through 6 [7] 
Case (q=2,d=1) → n = 0 through 4 [5] 
Case (q=2,d=2) → n = 0 through 2 [3] 
Case (q=2,d=3) → n = 0 [1] 

Total from case q=2: 1 + 3 + 5 + 7 = 16 

Case q=3 [ n + 2d ≤ 1 ] 
Here d must be 0, so there is only the case: 
Case (q=3,d=0) → n = 0 through 1 [2] 

So the case q=3 only has 2. 

Grand total: 2 + 16 + 42 + 81 = 141 </span>
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Answer:

{A and B are independent events}, P(A|B)=P(A)=0.16

Step-by-step explanation:

First of all we need to know when does two events become independent:

For the two events to be independent,  P(A|B)=P(A) that is if condition on one does not effect the probability of other event.

Here, in our case the only option that satisfies the condition for the events to be independent is  P(A|B)=P(A)=0.16.. Rest are not in accordance with the definition of independent events.

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Answer:

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