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Alja [10]
2 years ago
6

A bag contains 9 tiles, each with a different number from 1 to 9. you choose a tile without looking, put it aside, choose a seco

nd tile without looking, put it aside, then choose a third tile without looking. what is the probability that you choose tiles with the numbers 1, 2, and 3 in that order?
SAT
1 answer:
cluponka [151]2 years ago
5 0

The Probability that you choose tiles with the numbers 1, 2, and 3 in that order is; 0.198 %

<h3>How to find probability of selection?</h3>

We are told that the bag contains 9 tiles labelled from number 1 to 9.

Now, this means that;

Probability of first tile being 1 = 1/9

Since there is no replacement after selection;

Probability of second tile being 2 = 1/8

Probability of third tile being 3 = 1/7

Thus;

Probability that you choose tiles with the numbers 1, 2, and 3 in that order is;

P(1, 2, 3 order) = (1/9) * (1/8) * (1/7)

P(1, 2, 3 order) = 1/504 = 0.198%

Read more about Probability at; brainly.com/question/251701

#SPJ1

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Consider the table below and answer the probability question. Write your answer as a percentage rounded to 1 decimal.
N76 [4]

Answer:

P(Joe) = 0.3

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Explanation:

Solving (a): P(Joe)

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P(Joe\ \&\ North\ Side) = 0.2

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