Answer:
<em>The probability that the second ball is red is 71%</em>
Step-by-step explanation:
<u>Probabilities</u>
We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).
The first ball can be red (R) or green (G). The probability that it's red is computed by

The probability is's green is computed by

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

The total probability of the second ball being red is

The probability that the second ball is red is 71%
Multiply it out.
I believe the answer would be 15x^2 - 20x.
However, functions is not my forte.
Soooo
yeah
Answer:
1.8(3) (three is a repeating number)
Step-by-step explanation:
Divide the numerator from the denominator. Add the value of the integer part.
Let's expand the products they are all in the form

For the first one we have a=x and b=2i:

For the second one we have a=x-2 and b=2i:

For the third one we have a=x+1 and b=i:

The answer is 10 because 5 and 5 is 10