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WARRIOR [948]
2 years ago
12

A motorcycle that regularly sells for 1,450 was discounted by 40% off

Mathematics
1 answer:
marissa [1.9K]2 years ago
8 0

Answer:

$870.00 is the motorcycle price after a 40% discount

Step-by-step explanation:

discount = original price x discount % / 100

discount = 1450 x 40 / 100

discount = 1450 x 0.4

<u>discount = $580.00</u>

Final Price = Original Price - Discount

Final Price = 1450 - 580

<u>Final Price = $870</u>

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The stands at the soccer field can hold 40 people. The stands are 3/4 filled. Of the people in the stands, 5/6 are home team fan
AysviL [449]
It is given in the question that the stands of the soccer field has the capacity to hold 40 people. Also it is given that the stands of the soccer field is 3/4 filled.
Then,
The number of people in the stands = 40 * (3/4)
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So 30 people are in the stands of the soccer field.
Now among the people present in the stands of the soccer field, 5/6 are home fans and the rest are fans of the away team.
Then,
Number of home team fans = 30 * (5/6)
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So there are 25 home team fans present in the stand of the soccer field.
5 0
3 years ago
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k0ka [10]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
3 years ago
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zalisa [80]
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7 0
4 years ago
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Can someone help menplz
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