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adelina 88 [10]
2 years ago
8

I need help with this question

Mathematics
1 answer:
MariettaO [177]2 years ago
6 0
You would move the decimal two places to the left
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The cost to purchase 3 sandwich rolls is $0.48. How much will it cost to<br> purchase 20 rolls?
spayn [35]

Answer:

$3.2

Step-by-step explanation:

0.48 ÷ 3 = 0.16

0.16*20=3.20

Hope this helps

7 0
2 years ago
Read 2 more answers
Find the x- and y-intercepts for the graph of the equation: 9x-6y=3
erik [133]
<span>9x-6y=3
</span>x -intercepts y = 0, 9x = 3 then x = 1/3
y -intercepts x = 0, -6y = 3 then y = -1/2

answer
x -intercepts (1/3, 0)
y -intercepts (0, -1/2)
5 0
3 years ago
What is the cost of 4 pairs of Nikes if each pair is $365.68 along with 120 peaches that each cost $9.00? Help giving away 30 po
Nutka1998 [239]

Answer:

$2542.72 for everything

Step-by-step explanation:

$365.68*4=$1462.72 for the nikes

120*9.00=1080 for the peaches SO YOU ADD the $1462.72 and the *1080 which is $2542.72 for everything

6 0
2 years ago
Read 2 more answers
1
Scilla [17]

Answer:

124.51%

Step-by-step explanation:

In this problem, we are expected to solve for the percentage change, given the opening  point and the closing point

given that the low is 4014

and the high is  9012

the formula to calculate the percentage change is given as

%change= (high-low)/low*100

substituting our given data we have

%change= (9012-4014)/4014*100

%change= (4998)/4014*100

%change= (1.2451)*100

%change= 124.51%

The total change in the stock market from the beginning of the day to the end of the day is 124.51%

hope this helps

sorry if wrong

#Virgo2007

4 0
3 years ago
your friend deposits $9500 in an investment account that earns 2.1% annual interest. what is the balance after 11 years when the
solmaris [256]

Answer:

The answer is "$ 11,961.43"

Step-by-step explanation:

Given values:

P =  $ 9500

r= 2.1 %

time (t)= 11 year

total quarterly year =4

Formula:

A= P (1+\frac{r}{n})^{nt}\\\\

quarterly time = 4 \times 11

                         = 44

A= P (1+\frac{r}{n})^{nt}\\\\

A = 9500 ( 1+ \frac{0.021}{4})^{44}\\\\A = 9500(\frac{4+ 0.021}{4} )^{44} \\\\A = 9500(\frac{4.021}{4} )^{44} \\\\A= 9500 (1.00525)^{44}\\\\A= 9500(1.25909819)\\\\A= 11,961. 43\\

8 0
3 years ago
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