the answer is they can store more information
Answer:
look up the number (phone number) to call them and ask is they can cancel the account the debit card is abt to pay for :)
In cyber security, an exploit is a way attackers take advantage of certain vulnerabilities and gain malicious access to systems. There are very many types of exploits that exist in the cyber security world. However, I will mention those ones most commonly used.
DoS attacks – The denial of service attacks is very common. Hackers will gain access to servers and send so many packet requests at the same time. The servers become overwhelmed due to too much memory allocation and the huge amount of traffic ends up crashing the servers.
Unauthorized access – When an attacker has an illegal access to host machines
<u>Application Exploitation</u>
Code injection – This exploit can be used to maliciously inject invalid code into an application program or software and as a result change how the program behaves.
Cross-site scripting – Enable hackers inject malicious scripts on a website of a client. Once they have gained access, they will escalate their privileges and have more access to the site.
Clickjacking – A type of attack that tricks unknown victims into clicking links of a web page they believe are legitimate and end up revealing confidential information of themselves.
Answer: Configure a response for external senders.
Explanation:
Since Kylee wants to ensure that when a particular client sends her an email while she is on vacation, then the email will be forwarded to a coworker for immediate handling, then she should configure a response for external senders.
It should be noted that the response will not be configured for internal senders as it isn't from a co-worker but rather meant for a client. Therefore, the correct option is A.
import java.util.Scanner;
public class JavaApplication58 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter a positive integer:");
String num = scan.nextLine();
for (int i = num.length()-1; i >=0; i--){
System.out.println(num.charAt(i));
}
}
}
I hope this helps!
