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sweet [91]
2 years ago
14

A prime polynomial is an irreducible polynomial with integer coefficients that cannot be factored into polynomials of lower degr

ee over the real number system.
Which trinomial is prime?

x2 – 7x – 18
x2 – 9x – 18
x2 + 3x – 18
x2 + 17x – 18
Mathematics
1 answer:
Mariulka [41]2 years ago
8 0

Step-by-step explanation:

the point is for such a consideration :

the constant term (like -18 in our example here) is a×b.

and the factor of the x-term (like -7 of -7x) is a+b.

if there are 2 numbers a, b that satisfy these 2 conditions for a trinomial, than it is not prime as it can be factored.

x² - 7x - 18 is not prime.

what factors can create 18 ?

1×18

2×9

3×6

4×4.5

5×3.6

...

-7 = -9 + 2

so, it can be factored into

(x - 9)(x + 2)

x² - 9x - 18 is not prime

a×b = -18

a+b = -9

a = -9 - b

(-9 - b)b = -18

-9b - b² = -18

b² + 9b = 18

b² + 9b - 18 = 0

x² + 9b - 18 = 0

general solution to a quadratic equation :

x = (-b ± sqrt(b² - 4ac))/(2a) = (-9 ± sqrt(9² - 4×1×-18))/(2×1) =

= (-9 ± sqrt(81 + 72))/2 = (-9 ± sqrt(153))/2

x1 = b1 = (-9 + sqrt(153))/2 = 1.684658438... = a2

x2 = b2 = (-9 - sqrt(153))/2 = -10.68465844... = a1

so, we can factor this into

(x + 1.684658438...)(x - 10.68465844...)

or

(x + (-9 + sqrt(153))(x + (-9 - sqrt(153))

these are not rational but still real numbers.

x² + 3x - 18 is not prime

based on the previous 2 examples we can factor this

(x + 6)(x - 3)

x² + 17x - 18 is not prime

based on the same principles this can be factored

(x + 18)(x - 1)

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