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Afina-wow [57]
2 years ago
15

24 3 Ans a. Define the term computer hardware. b. C. What are input devices? List any two input devices. What is processing devi

ce? Write the name of processing devices d. What are output devices? Name any two common output devices Differentiate between soft copy output and hard copy output? f. What are storage devices? Write two such devices. e. g. What is primary memory? What are its types. h. What are the differences between RAM and ROM? i. What is CPU? List its major parts. j. Write short notes on the following: i. Keyboard Rising School Level Computer Science - 6 ii. Control unit iii. Printer​
Computers and Technology
1 answer:
marysya [2.9K]2 years ago
8 0

Explanation:

hardware are the physical parts of the computer which can be touched seen and felt is called hardware.

the device which are use to inter data and instructions from the user is clawed input device. foreg; keyboard , mouse.

the processing device of computer is cpu

the printed information which can be touched and seen is Called hardcopy .

soft copy are which can be seen but not touched is called soft copy .

the device that are use to store data and instructions is called storage devices.

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During the data transmission there are chances that the data bits in the frame might get corrupted. This will require the sender
pashok25 [27]

1. Based on Scenario A, the packets should be encapsulated in multiple frames to minimize the re-transmission overhead.

This is because there will be the need to re-transmit the packets because the network environment is not reliable and accurate.  Therefore, a single frame may be too costly when the need for re-transmission arises.

2. Based on Scenario B, the packets should be encapsulated in a single frame because of the high level of network reliability and accuracy.  

There will not be further need to re-transmit the packets in a highly reliable and accurate network environment.  This environment makes a single frame better.

Encapsulation involves the process of wrapping code and data together within a class so that data is protected and access to code is restricted.

With encapsulation, each layer:

  • provides a service to the layer above it
  • communicates with a corresponding receiving node

Thus, in a reliable and accurate network environment, single frames should be used to enhance transmission and minimize re-transmission overhead.

Learn more about data encapsulation here: brainly.com/question/23382725

5 0
3 years ago
Para saan po yung points dito?
PilotLPTM [1.2K]

Answer:

Hindi kudin Alam eh hahahha

7 0
3 years ago
How to check the at&t internet speed on my computer
Advocard [28]

Answer:

You can use the speedtest.net website. AT&T also has their own tool here: https://www.att.com/support/speedtest/

6 0
2 years ago
er reports that he is having problems with his monitor. He explains that his laptop's liquid crystal display (LCD) is no longer
kati45 [8]

Answer:

diffuser

Explanation:

Based on the scenario being described, the most likely cause of the problem is a bad diffuser. This is a component found in nearly every type of LCD backlit displays and are used to produce an even array of lighting across the entire display. If this component fails then it will cause bright spots and dim spots throughout the display, similar to what the client is reporting in this scenario since the light is not being evenly distributed.

4 0
3 years ago
Write a program that reads in 10 numbers from the user and stores them in a 1D array of size 10. Then, write BubbleSort to sort
Diano4ka-milaya [45]

Answer:

The solution is provided in the explanation section.

Detailed explanation is provided using comments within the code

Explanation:

import java.util.*;

public class Main {

//The Bubble sort method

public static void bb_Sort(int[] arr) {  

   int n = 10; //Length of array  

   int temp = 0; // create a temporal variable  

   for(int i=0; i < n; i++){  

         for(int j=1; j < (n-i); j++){  

           if(arr[j-1] > arr[j]){  

               // The bubble sort algorithm swaps elements  

               temp = arr[j-1];  

               arr[j-1] = arr[j];  

               arr[j] = temp;  

             }  

         }            

         }  

        }

 public static void main(String[] args) {

   //declaring the array of integers

   int [] array = new int[10];

   //Prompt user to add elements into the array

   Scanner in = new Scanner(System.in);

   //Use for loop to receive all 10 elements

   for(int i = 0; i<array.length; i++){

     System.out.println("Enter the next array Element");

     array[i] = in.nextInt();

   }

   //Print the array elements before bubble sort

   System.out.println("The Array before bubble sort");

   System.out.println(Arrays.toString(array));

   //Call bubble sort method

   bb_Sort(array);  

               

   System.out.println("Array After Bubble Sort");  

   System.out.println(Arrays.toString(array));

 }

}

8 0
3 years ago
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