Hypotenuse^2 = leg1^2 + leg2^2
3^2 = 2^2 + leg2^2
leg2^2 = 3^2 -2^2
leg2^2 =9 -4
leg2^2 = 5
leg2 = square root (5)
Answer:
D
Step-by-step explanation:
For simplify the work we can start to factorise all the possibles expressions:
2x + 8.
8 is multiple of 2, so it can became
2(x+4)
x^2 - 16 this is a difference of two squares, so it can be rewritten as:
(x+4)(x-4)
x^2 + 8x + 16
we have to find two numbers whose sum is 8 and whose product is 16
the two number are 4 and 4
it becames:
(x+4)(x+4)
x+ 4 can‘t be simplified
if we look at the expression, we can find that x-4 appears at the numerator so
x^2 - 16 must be at numerator
but the second factor (x+4) doesn’t appear, so has been simplified. This situation can be possible only in the D option
in fact
(x+4)(x-4)/2(x+4) * (x+4)/(x+4)(x+4)
it became
(x+4)(x-4)/2 * 1/(x+4)(x+4)
(x-4)/2(x+4)
Actually you would need 125 inches cube:
5 inches of length × 5 inches of height × 5 inches of width which equals to 125 inches cube !
I hope you understood my brief explanation. And please consider marking this awnser as Branliest. Thank you ! :)
The property of exponents says that when you divide two exponents with the same base, you can keep the base and subtract the exponents. So you can do 18-3, which is 15, so it would be 15 to the 15th power