Answer:
She has 45 Bottles left after drinking them
Step-by-step explanation:
This question needs some more clarification!
From what I read!
We know that Janelle has brought 4 cases of water containing 12 bottles in 1 case.
If she were to drink 3 bottles of water how much bottles will she have left?
First, we would have to do a multiplication problem involving the cases of water and how much bottles in one case.
Equation: 4 Cases x 12 Bottles in Each Case=48 Bottles in Total
Then, Janelle has drunk 3 bottles of water already, so we would need to subtract.
Equation 48 Bottles in Total - 3 Bottles Drunk = 45 Bottles in Total
Therefore, Janelle has 45 Bottles left in her inventory.
Answer:
Step-by-step explanation:
su - -rqt
u = -rqt/s
Answer:
18a(2bc + 3d)
Step-by-step explanation:
36abc + 54ad
Step 1: Find the Highest Common Factor of each
36abc = 2×2×3×3×a×b×c = 18a × 2bc
54ad = 2×3×3×3×a×d = 18a × 3d
HCF = 2×3×3×a = 18a
Step 2: Factor out with HCF
18a(2bc + 3d)
A = 18
You need to
Multiply both sides of the equation
- 3/2 x (-2/3) x a = - 3/2 x - 12
Then simplify both sides
a = - 3/2 x 12
Simplify
-3/2 x -12
a = -3 x -6
Multiply -3 by -6
Answer: a = 18
