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aliya0001 [1]
2 years ago
7

3. Twelve people work together: four of them are managers and eight of them are office workers. Two people are chosen at random

from the twelve members of the group. Calculate the probability that one is a manager and one is an office worker.​
Mathematics
1 answer:
kirill [66]2 years ago
8 0

Answer:

2/9

Step-by-step explanation:

8/12 you pick an office worker

4/12 chance you pick a manager

8/12 multiplied by 4/12 is 32/144

We can simplify this to 16/72

We can simplify this to 8/36

We can simplify this to 4/18

We can simplify this to 2/9

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Twice the sum of four and x is three less than x.
aliya0001 [1]

Answer:

-11

Step-by-step explanation

Condition:

2(4+x)=x-3

8+2x=x-3

Combining similar terms

8+3=x-2x

11=-x

OR

x=-11

7 0
3 years ago
PLEASE HELP ME!!!!!! CLICK ON THIS PLEASE
Serhud [2]

Answer:

a) ok, heres what u graph, and ur ordered pairs

graph the following points:

(0,0) (1,5) (2,10) (3,15) (4,20) (5,25) (6,30) (7,35), and so on

b) One of the ordered pairs I can use is (1,5). This is beacuse the ordered pair explains that for every video game (x), 5 will be the cost (y).

7 0
3 years ago
Read 2 more answers
If the point (x, -2) is a solution to the equation y = 2x – 4, find the value of x.
guapka [62]
This should your answer:

X = 4

7 0
2 years ago
Read 2 more answers
Solve using a proportion.
Advocard [28]

Answer:

t = 24 yards

Step-by-step explanation:

Since the trapezoids are similar then the ratios of corresponding sides are equal, that is

\frac{t}{c} = \frac{u}{d}

Substitute in given values

\frac{t}{0.4} = \frac{15}{0.25} ( cross- multiply )

0.25t = 6 ( divide both sides by 0.25 )

t = 24

5 0
3 years ago
A diameter of a circle has enpoints (-2, 10) and (6, -4) in the standard (x, y) coordinate plane. What is the center of the circ
wlad13 [49]

Answer:

The center of the circle is C(x,y) = (2, 3).

Step-by-step explanation:

The center of the circle is the midpoint of the segment between the endpoints. We can determine the location of the center by this vectorial expression:

C(x,y) = \frac{1}{2}\cdot R_{1}(x,y)+ \frac{1}{2}\cdot R_{2}(x,y) (1)

Where:

C(x,y) - Center.

R_{1} (x,y), R_{2} (x,y) - Location of the endpoints.

If we know that R_{1} (x,y) = (-2,10) and R_{2} (x,y) = (6,-4), then the location of the center of the circle is:

C(x,y) = \frac{1}{2}\cdot (-2,10)+\frac{1}{2}\cdot (6,-4)

C(x,y) = (-1, 5) + (3, -2)

C(x,y) = (2, 3)

The center of the circle is C(x,y) = (2, 3).

8 0
3 years ago
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