Answer:
When looking at this model, and asking yourself the question, is PRB congruent to QSB? PRB is in fact congruent to QSB. Congruent means that two figures have the same shape/size, no matter if it's mirrioring or not it is congruent. In this image, PRB is one shape, and QSB is another. They have the exact same points and they're also the same shape, but one is flipped the right side up. It was also stated PQ and RS bisect eachother at point B, <p is congruent to <Q, and <R is congruent to <S proving all these connections make this figure conguent.
Step-by-step explanation:
![y' = \frac{dy}{dx}](https://tex.z-dn.net/?f=y%27%20%3D%20%5Cfrac%7Bdy%7D%7Bdx%7D%20)
seperable differential equations will have the form
![\frac{dy}{dx} = F(x) G(y)](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D%20F%28x%29%20G%28y%29)
what you do from here is isolate all the y terms on one side and all the X terms on the other
![\frac{dy}{G(y)} = F(x) dx](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7BG%28y%29%7D%20%3D%20F%28x%29%20dx)
just divided G(y) to both sides and multiply dx to both sides
then integrate both sides
![\int \frac{1}{G(y)} dy = \int F(x) dx ](https://tex.z-dn.net/?f=%5Cint%20%5Cfrac%7B1%7D%7BG%28y%29%7D%20dy%20%3D%20%5Cint%20F%28x%29%20dx%0A%0A)
once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it
In your problem,
![G(y) = \sqrt{1-y^2} F(x) = 2x](https://tex.z-dn.net/?f=G%28y%29%20%3D%20%5Csqrt%7B1-y%5E2%7D%0A%0AF%28x%29%20%3D%202x)
so all you need to integrate is
Answer:
12326391
Step-by-step explanation:
Answer:
8/52
Step-by-step explanation:
There are 4 Jacks and 4 Queens in a deck of 52 cards, bumping the odds up to 8/52.