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eduard
2 years ago
8

The surface area of the triangular pyramid 12 ft. 6 ft 5.2 ft

Mathematics
1 answer:
Rzqust [24]2 years ago
4 0
Add the little numbers and make 12 and 5.2 and 6ft next then you will have 7+12+6=25 area
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HOW WOULD YOU DO THIS???
arlik [135]
Well to start off with, this is an intersecting angle. as you can see, on part is already at a 60 degree angle. each angle inside is an acute angle, but they are still equal to each other.

because of this, you have to look at the angle inside of this (the acute angle)

both X and Y would also be 60 degrees...

hope this helps!
4 0
4 years ago
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Giles made baklava to serve at a party. He cut it into parallelogram-shaped pieces with the dimensions shown below Whoever gets
Nana76 [90]

Answer:

B

Step-by-step explanation:

7 0
4 years ago
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Find the equation of a line in slope intercept form that is perpendicular to the line y = 2x + 6 through the point (10,4)
dalvyx [7]

The equation of the straight line is y = -1/6(x - 10) + 4

<h3>How to determine the line equation?</h3>

The equation is given as:

y = 2x + 6

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y = mx + c

Where:

Slope = m

So, we have:

m = 6

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n = -1/m

So, we have:

n = -1/6

The equation is then represented as:

y = n(x - x1) + y1

This gives

y = -1/6(x - 10) + 4

Hence, the equation of the straight line is y = -1/6(x - 10) + 4

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6 0
2 years ago
Convert these sums into decimal.
alex41 [277]
A) 0.6
b) 0.65
c) 0.104
d) 0.32
7 0
3 years ago
The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{236100}{8} = 29512.5

Sum of squares of differences = 3408750

S.D = \sqrt{\frac{3408750}{7}} = 697.82

Population mean, μ = $30,000

Sample mean, \bar{x} = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars} We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975

Now,

t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894

Since,                  

t_{stat} < t_{critical}

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

8 0
4 years ago
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