The picture is a little blurry
I don't know if you mean this as a linear equation?
if so a = x-6 over c
Answer:
n = 1, A = $2,191.12
n = 2, A = $2,208.04
n = 4, A = $2216.71
n = 12, A = $2222.58
n = 365, A = $2225.44
Compound continuously, A = $2,225.54
Step-by-step explanation:
We are given the following in the question:
P = $1000
r = 4% = 0.04
t = 20 years
Formula:
The compound interest is given by
![A = P\bigg(1 + \displaystyle\frac{r}{n}\bigg)^{nt}](https://tex.z-dn.net/?f=A%20%3D%20P%5Cbigg%281%20%2B%20%5Cdisplaystyle%5Cfrac%7Br%7D%7Bn%7D%5Cbigg%29%5E%7Bnt%7D)
where P is the principal, r is the interest rate, t is the time, n is the nature of compound interest and A is the final amount.
For n = 1
![A = 1000\bigg(1 + \displaystyle\frac{0.04}{1}\bigg)^{20}\\\\A = \$2,191.12](https://tex.z-dn.net/?f=A%20%3D%201000%5Cbigg%281%20%2B%20%5Cdisplaystyle%5Cfrac%7B0.04%7D%7B1%7D%5Cbigg%29%5E%7B20%7D%5C%5C%5C%5CA%20%3D%20%5C%242%2C191.12)
For n = 2
![A = 1000\bigg(1 + \displaystyle\frac{0.04}{2}\bigg)^{40}\\\\A = \$2,208.04](https://tex.z-dn.net/?f=A%20%3D%201000%5Cbigg%281%20%2B%20%5Cdisplaystyle%5Cfrac%7B0.04%7D%7B2%7D%5Cbigg%29%5E%7B40%7D%5C%5C%5C%5CA%20%3D%20%5C%242%2C208.04)
For n = 4
![A = 1000\bigg(1 + \displaystyle\frac{0.04}{4}\bigg)^{80}\\\\A = \$2216.71](https://tex.z-dn.net/?f=A%20%3D%201000%5Cbigg%281%20%2B%20%5Cdisplaystyle%5Cfrac%7B0.04%7D%7B4%7D%5Cbigg%29%5E%7B80%7D%5C%5C%5C%5CA%20%3D%20%5C%242216.71)
For n = 12
![A = 1000\bigg(1 + \displaystyle\frac{0.04}{12}\bigg)^{240}\\\\A = \$2222.58](https://tex.z-dn.net/?f=A%20%3D%201000%5Cbigg%281%20%2B%20%5Cdisplaystyle%5Cfrac%7B0.04%7D%7B12%7D%5Cbigg%29%5E%7B240%7D%5C%5C%5C%5CA%20%3D%20%5C%242222.58)
For n = 365
![A = 1000\bigg(1 + \displaystyle\frac{0.04}{365}\bigg)^{7300}\\\\A = \$2225.44](https://tex.z-dn.net/?f=A%20%3D%201000%5Cbigg%281%20%2B%20%5Cdisplaystyle%5Cfrac%7B0.04%7D%7B365%7D%5Cbigg%29%5E%7B7300%7D%5C%5C%5C%5CA%20%3D%20%5C%242225.44)
Compounded continuously:
![A = Pe^{rt}\\A = 1000e^{0.04\times 20}\\A = $2,225.54](https://tex.z-dn.net/?f=A%20%3D%20Pe%5E%7Brt%7D%5C%5CA%20%3D%201000e%5E%7B0.04%5Ctimes%2020%7D%5C%5CA%20%3D%20%242%2C225.54)
The greatest whole humber like that is 987654321
Answer:
that formula is known as the Pythagorean theorem