2 years ago

In right triangle PQR , PQ=12 cm and QR=5cm .What is cos R?

Mathematics

1 answer:

Juliette [100K]2 years ago

7 0

Answer:

cosR = $\frac{5}{13}$

Step-by-step explanation:

assuming the right triangle has ∠ Q = 90° with legs 5 and 12

then this is a 5- 12- 13 right triangle with hypotenuse PR = 13 cm

then

cosR = $\frac{adjacent}{hypotenuse}$ = $\frac{QR}{PR}$ = $\frac{5}{13}$

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