Question

In right triangle PQR , PQ=12 cm and QR=5cm .What is cos R?

Answer 1

Answer:

cosR = $\frac{5}{13}$

Step-by-step explanation:

assuming the right triangle has ∠ Q = 90° with legs 5 and 12

then this is a 5- 12- 13 right triangle with hypotenuse PR = 13 cm

then

cosR = $\frac{adjacent}{hypotenuse}$ = $\frac{QR}{PR}$ = $\frac{5}{13}$