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nekit [7.7K]
2 years ago
7

In right triangle PQR , PQ=12 cm and QR=5cm .What is cos R?

Mathematics
1 answer:
Juliette [100K]2 years ago
7 0

Answer:

cosR = \frac{5}{13}

Step-by-step explanation:

assuming the right triangle has ∠ Q = 90° with legs 5 and 12

then this is a 5- 12- 13 right triangle with hypotenuse PR = 13 cm

then

cosR = \frac{adjacent}{hypotenuse} = \frac{QR}{PR} = \frac{5}{13}

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A quarter circle is attached to the side of a square that is 8 cm.
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3 years ago
Somebody please help me?​
Natalija [7]

The events A and B are independent events, and the values of P(A) and P(B) are 7/12 and 1/2, respectively

<h3>The value of P(A)</h3>

The event A is given as:

A : Sum greater than 6

In the sample space of a roll of two dice, there are 21 outcomes that are greater than 6, out of a total of 36 outcomes

This means that:

P(A) = 21/36

Simplify

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<h3>The value of P(B)</h3>

The event B is given as:

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This means that:

P(B) = 18/36

Simplify

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5 0
1 year ago
Write the equation of the line that passes through the points (1,9) and (-1,1). Put
SpyIntel [72]

Answer:

Point slope form

                 y - 9 = 4(x-1)

Equation of the straight line passing through the point (1,9) and slope 'm' = 4 is    4 x - y +5=0

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the points are (1,9) and (-1,1)

slope of the line

                m = \frac{y_{2}-y_{1}  }{x_{2} - x_{1} }

               m = \frac{1-9}{-1-1}

             m = 4

<u><em>step(ii):-</em></u>

Equation of the straight line passing through the point (1,9) and slope 'm' = 4

                     y-y₁ = m( x-x₁)

                   y - 9 = 4(x-1)

                  y -9 = 4x-4

           4 x - y -4+9 =0

          4 x - y +5=0

Equation of the straight line passing through the point (1,9) and slope 'm' = 4 is    4 x - y +5=0

7 0
2 years ago
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