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STatiana [176]
2 years ago
9

HELP PLSS

Mathematics
1 answer:
Elza [17]2 years ago
5 0

Answer:

Reflexive property of congruence

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Compare Fractions<br>Compare. Write &gt;,&lt;, or =<br>1/5 1/15
defon

Answer:

\frac{1}{5}  \: and \:  \frac{1}{15}

Both of these must have similar denominators:

\frac{3}{15}  \: and \:  \frac{1}{15}  \\  \frac{3}{15}  \: i s \: \: more \: than \:   \frac{1}{15}  \\  \frac{3}{15}  >  \frac{1}{15}

Good luck!

Intelligent Muslim,

From Uzbekistan.

4 0
3 years ago
What is 174/216 in simplify form
masha68 [24]
 174/216 in simplify form is 35/54

7 0
3 years ago
Read 2 more answers
I have a couple more questions and I don’t have time to answer them all lol, my science class starts in 15 minutes.
Semmy [17]

Answer:

\boxed{x = 7}

Step-by-step explanation:

75 = 11x-2 <u><em>(Corresponding angles are equal)</em></u>

11x -2 = 75

Adding 2 to both sides

11x = 75+2

11x = 77

Dividing both sides by 11

x = 7

5 0
3 years ago
Read 2 more answers
Evaluate the piecewise-defined function for the indicated values. I’m just unsure of how to solve when the value isn’t given dir
Fantom [35]

The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for m^{2} +1 is 9.

Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and \sqrt{t-1} for 8<t<11.

A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.

B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.

C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.

D) In this we have to find the function at m^{2} +1 when m belongs to \sqrt{7} and \sqrt{10} the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.

Learn more about functions at brainly.com/question/10439235

#SPJ10

6 0
2 years ago
Which expression is the simplest form of (27x^-9)^1/3?
lana [24]
\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\\\(a^n)^m=a^{nm}\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(27x^{-9})^\frac{1}{3}=27^\frac{1}{3}(x^{-9})^\frac{1}{3}=\sqrt[3]{27}\cdot x^{-9\cdot\frac{1}{3}}=3x^{-3}=\dfrac{3}{x^3}
8 0
3 years ago
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