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jekas [21]
2 years ago
9

Find the indicated second-order partial derivative for fyx if f(x,y)=e3x+2y

Mathematics
1 answer:
Verdich [7]2 years ago
5 0
Fy = 2 because we derivate in raport witw y and x is like a constant;
fyx = 0 because we deivare in raport with x.
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8 0
2 years ago
-2 2 the second power<br>​
Novosadov [1.4K]
-4 or -484
if it’s -2 to the 2nd power then it is -4
or if it’s -22 to the 2nd power then it is -484
3 0
3 years ago
Dawn has 5\6 yard of lace. She uses 4\5 of it on a dress and the rest on a jewel box. How much does she use on the jewel box
mr_godi [17]

Answer:

Jewelry box:  1/6 yard

Step-by-step explanation:

4/5 (not 4\5) of her 5/6 yard goes into a dress:   (4/5)(5/6 yd) = 2/3 yard.

This is the same as 4/6 yard.  The amount of lace remaining, to be used on a jewelry box, is 5/6 - 4/6, or 1/6 yard.

3 0
3 years ago
Name the missing coordinate(s) of each triangle
Cloud [144]

Answer:

13) C (a, a)  Y (a, 0)

14) B (0, b)  P (a, 0)

Step-by-step explanation:

13) Y lies on x axis so it is Y(a,0)

ZY = YC = a

so for C coordinates are (ZY,YC) = (a, a)

14) B lies on y axis so it is B(0, b)

BK = BP = \sqrt{a^{2} + b^{2}  } = distance between two points

so P is (a, 0) as it is same distance and on positive side of x axis

3 0
2 years ago
Read 2 more answers
74% of 19 year old males are atleast 172 pounds , what percent of the males are not atleast 172 pounds?
swat32

Answer:

<em>The percentage of males are not at least 172 pounds</em>

P(X⁻ ≥ 172) = 0.26

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that 74% of 19 -year -old males are at least 172 pounds

Let 'X' be a random variable in a binomial distribution

P( X≥172) = 74% = 0.74

<em>we have to find that the percentage of males are not at least 172 pounds</em>

<u><em>Step(ii):-</em></u>

<em>The probability of males are not at least 172 pounds</em>

P(X⁻≥172) = 1- P( X≥172)

                 = 1- 0.74

<em>                  = 0.26</em>

<u><em>Final answer:-</em></u>

<em>The percentage of males are not at least 172 pounds</em>

P(X⁻ ≥ 172) = 0.26

<u><em></em></u>

7 0
2 years ago
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