Question

(Will give 25 points!) Solve the system of linear equations by substitution. 3x - 2y = 12 and 4x + 2y = 16

Answer 1

Let

Eq1 : x - 2y = 12

Eq2 : 4x + 2y = 16

For substitution, we need to rearrange on of the equations so that we can substitute it in the other. Let's pick eq2 and rewrite it as 2y = 16 - 4x. We see that eq1 also has 2y in it, so we can plug this new version of eq2 in there.

3x - (16-4x) = 12

Now solve for x.

7x=28, so x=4

Plug that into either equation to solve for y. You get y=0.

So your answer is x=4, y=0

Answer 2

Answer:

i think its X squared=y squared +4

Step-by-step explanation:

thats what i got